100 J
Please mark me brainliest it would be greatly appreciated haha
Answer:
t = 1.42 s and d = 35.5 m
Explanation:
Given that,
Velocity of a roadrunner is 25 m/s
A certain coyote wants to capture the roadrunner using a net dropped from an overpass that is 10 m high.
We need to find the time before the roadrunner is under the overpass and how far away from the overpass is the roadrunner when the coyote drops the net.

Let d is the distance traveled. So,
d = vt
d = 25 m/s × 1.42 s
d = 35.5 m
Since the direction of the force and the direction of the path is perpendicular, the person is not doing any physical work.
I wanna say B Red-billed oxpeckers eat ticks off of impalas