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3 years ago

Water can be made to boil at 105 degrees Celsius instead of 100 degrees Celsius by

1 answer:

4 0

The answer to the question is letter 'C', water can be made to boil at 105 degrees Celsius by decreasing the air pressure on the water. Boiling occurs when the water is hot enough to have the same pressure as the surrounding air. at high altitudes the air pressure is lower than the sea level, it possible that the boiling of water can be raise until 105 degrees.

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RUDIKE [14]

Answer:

The exhaust system of the car is the excretory system that removes waste.

The gas in the car is the digestive system that provides the necessary energy.

3 0

3 years ago

Thermochemical equations are chemical equations that include the __________ of the reaction.

irga5000 [103]

A Thermochemical Equation is a balanced stoichiometric chemical equation that includes the enthalpy change, ΔH. In variable form, a thermochemical equation would look like this:

A + B → CΔH = (±) #

Where {A, B, C} are the usual agents of a chemical equation with coefficients and “(±) #” is a positive or negative numerical value, usually with units of kJ.

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5 0

3 years ago

How would I draw this? Thank you in advance!<br> (Z)-4-chloro-3-methylhept-2-ene

Savatey [412]

Answer:

In the attached photo.

Explanation:

Hello,

You could find the structure in the attached photo, taking into account that the initial (Z) resembles to the trans arrangement for this alkene.

Best regards.

3 0

3 years ago

Using the systematic approach for equilibrium problems, calculate the pH of 0.05 M HOCl. Ka= 3.0*10-8 Group of answer choices 3.

SVEN [57.7K]

Answer:

The pH is equal to 4.41

Explanation:

Since HClO is a weak acid, its dissociation in aqueous medium is:

HClO ⇄ ClO- + H+

start: 0.05 0 0

change -x +x +x

balance 0.05-x x x

As it is a weak acid it dissociates very little, in its ClO- and H + ions, so the change is negative, where x is a degree of dissociation.

the acidity constant when equilibrium is reached is equal to:

$Ka=\frac{[ClO-]*[H+]}{[HClO]}=\frac{x*x}{0.05-x}=3x10^{-8}$

The 0.05-x fraction can be approximated to 0.05, because the ionized fraction (x) is very small, therefore we have:

$3x10^{-8}=\frac{x^{2} }{0.05}$

clearing the x and calculating its value we have:

$x=3.87x10^{-5}=[H+]=[ClO-]$

the pH can be calculated by:

$pH=-log[H+]=-log[3.87x10^{-5}]=4.41$

7 0

3 years ago

The enthalpy of neutralization for the reaction of a strong acid with a strong base is −56 kJ/mol of water produced. How much en

denis23 [38]

Answer:

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Explanation:

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6 0

3 years ago