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Dmitriy789 [7]
3 years ago
14

1. Assume that EAX contains ff ff ff 51 and the doubleword referenced by value contains ff ff ff f1.

Engineering
1 answer:
IRINA_888 [86]3 years ago
6 0

Answer:

1. True

2. False

Explanation:

given data

EAX contains =  ff ff ff 51

doubleword referenced = ff ff ff f1

conditional jump add = eax

solution

1st statement is true

but 2nd statement is false

as here

  • js or jne instruction is the conditional jump that is follow a test
  • It jump to the specified location when  previous instructions are set the SF (Sign Flag) .
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134a refrigerant enters an adiabatic compressor at 140kPa and -10C, the refrigerant is compressed at 0.5kW up to 700kPa and 60C.
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Answer:

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(b) 16.91%

Solution:

As per the question:

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At outlet:

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At outlet, at  P = 140 kPa, T =- 10^{\circ}C:

h' = 296.69 kJ/kg, s' = 1.0182 kJ/kg.K

Also in isentropic process, s = s'_{s} and h'_{s} = 278.06 kJ/kg.K at 700kPa

(a) Isentropic efficiency of the compressor, \eta_{s} = \frac{Work\ done\ in\ isentropic\ process}{Actual\ work\ done}

\eta_{s} = \frac{h'_{s} - h}{h' - h} = frac{278.06 - 243.40}{296.69 - 243.40} = 0.6504 = 65.04%

(b) The temperature of the environment, T_{e} = 27^{\circ}C = 273 + 27 = 300 K

Availability at state 1, \Psi = h - T_{e}s = 243.40 - 300\times 0.9606 = - 44.78 kJ/kg

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\eta' = \frac{\Psi' - \Psi}{h' - h} = \frac{- 8.77 - (- 44.78)}{296.69 - 243.40} = 0.6757 = 67.57%

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The final position of a car can be predicted with the following equation: Position = -2.5 (time) + 25 Where is the car’s positio
nekit [7.7K]

Answer:

The car's position at 3.0 seconds is 17.5 meters. The car will reach 0.0 meters at 10 seconds.

Explanation:

You can rewrite the equation as P= -2.5t+25. t=time and P is equal to position; so you will plug in 3.0 seconds into t. The equation will now look like: P = -2.5(3.0)+25

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10 = t

So the car will reach 0.0 meters at 10 seconds.

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