Complete question:
(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C
Answer:
The energy that must be supplied to boil the given mass of the water is 672,000 J
Explanation:
Given;
mass of water, m = 2 kg
heat of vaporization of water, L = 330 kJ/kg
initial temperature of water, t = 20 ⁰C
specific heat capacity of water, c = 4200 J/kg⁰C
Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;
Q = mc(100 - 20)
Q = 2 x 4200 x (80)
Q = 672,000 J
Q = 672,000 J
Q = 672,000 J
Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J
Answer:
A) Diagonals of a parallelogram bisect each other
Answer:
(a) 
(b) 
Explanation:
For part (a)
As we know that

For part (b)
The power in unit of horsepower is:

Answer:

Explanation:
Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:
(1)
Where:






In this case:

Because the dog jumps horizontally
Let's asume the gravity constant as:


Because when the dog reach the base the height is 0


Now let's replace the data in (1)

Isolating t:

Finally let's find the horizontal displacement using this equation:

Replacing the data:
