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Svet_ta [14]
3 years ago
9

What is the average speed of an alien space ship that traveled 10,000 km in 600 hours?

Physics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

17,500 miles per hour

Explanation:

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A lava flow is an example of what igneous rock
nydimaria [60]
The answer is extrusive. 
7 0
4 years ago
Read 2 more answers
(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 3
Lelu [443]

Complete question:

(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C

Answer:

The energy that must be supplied to boil the given mass of the water is 672,000 J

Explanation:

Given;

mass of water, m = 2 kg

heat of vaporization of water, L =  330 kJ/kg

initial temperature of water, t = 20 ⁰C

specific heat capacity of water, c = 4200 J/kg⁰C

Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;

Q = mc(100 - 20)

Q = 2 x 4200 x (80)  

Q = 672,000 J

Q = 672,000 J

Q = 672,000 J

Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J

8 0
3 years ago
Answer:
Arlecino [84]

Answer:

A) Diagonals of a parallelogram bisect each other

6 0
4 years ago
Because it can go from rest to 14.2 m/s (about 32 mi/h) in 2.1 s, one of the fastest-accelerating animals is the cheetah. If its
TEA [102]

Answer:

(a) P_{power}=2688.53Watt

(b) P_{power}=3.605hp

Explanation:

For part (a)

As we know that

P_{power}=\frac{W_{work}}{t_{time}}\\As\\ W=1/2(mv_{f}^{2}-mv_{o}^{2} )So\\P_{power}=\frac{1/2(mv_{f}^{2}-mv_{o}^{2} )}{t}\\ P_{power}=\frac{1/2(56.0kg*(14.2m/s)^2-56.0kg*(0m/s)^2)}{2.1s} \\P_{power}=2688.53Watt

For part (b)

The power in unit of horsepower is:

P_{power}=(2688.53Watt)(\frac{1hp}{745.7Watt} )\\P_{power}=3.605hp

6 0
3 years ago
A dog leaps horizontally off a 70 m cliff with a speed of 6 m/s, how far from the base will the dog land?
iris [78.8K]

Answer:

\Delta x=22.67786838m

Explanation:

Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:

y-y_0=v_o*sin(\theta)*t-\frac{1}{2}*t^2 (1)

Where:

y=Final\hspace{3}position\hspace{3}at\hspace{3}y-axis

y_o=Initial\hspace{3}position\hspace{3}at\hspace{3}y-axis

v_o=initial\hspace{3}velocity

t=travel\hspace{3}time

g=gravity\hspace{3}constant

\theta=Initial\hspace{3}launch\hspace{3}angle

In this case:

\theta=0

Because the dog jumps horizontally

Let's asume the gravity constant as:

g=9.8

y=0

Because when the dog reach the base the height is 0

y_o=70

v_o=6

Now let's replace the data in (1)

y_o-\frac{1}{2} *(9.8)*t^2+70

Isolating t:

t=\pm\sqrt{\frac{2*70}{9.8} } =3.77964473

Finally let's find the horizontal displacement using this equation:

\Delta x=v_o*cos(\theta)*t

Replacing the data:

\Delta x=6*1*3.77964473=22.67786838m

8 0
3 years ago
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