Answer:
The answer to your question is a = -1.85 m/s² the acceleration is negative because it is coming to stop.
Explanation:
Data
vo = 25 m/s
t = 13.5 s
a= ?
vf = 0 m/s
Formula
vf = vo + at
solve for a
a = (vf - vo)/t
Substitution
a = (0 - 25) / 13.5
Simplification
a = -25/13.5
Result
a = -1.85 m/s²
First, we will get the distance traveled before the driver applied the brakes.
distance = velocity * time
distance = 25*0.34 = 8.5 m
Now, we will calculated the distance that the car traveled after the driver applied the brakes. To do this, we will use the equation of motion:
<span>vf^2 = vi^2 + 2*a*d where:
</span>vf = zero, vi = 25 m/s and a = -7 m/s^2
Note: The negative sign is only to show deceleration
d = <span> 1/2*(625) /(7) = 44.6428 m
The total stopping distance =</span> 8.5 + 44.6428 = 53.1428 m
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Explanation:
Rhythms that occur faster and slower than the beat are b.<span>not synchronized with the time signature. The synchronization follows the same beat or rhythm. If the time signature say is lower than the original, then the rhythm should be faster. Otherwise, the rhythm is slower than the original one.</span>