Answer:
101.19keV
Explanation:
r1 = 1.0cm = 0.01m
r2 = 1.90cm = 0.019m
B = 0.050T
q = 1.60*10^-19C
m = 9.11 * 10^-31 kg
Mv /r = qB
v = rqB / m
v1 = (0.01 * 1.60*10^-19 * 0.05) / 9.11 * 10^-31
v1 = 8.78 * 10⁷ m/s
V2 = (0.019 * 1.60*10^-19 * 0.05) / 9.11 * 10^-31
V2 = 1.67 * 10⁸ m/s
Kinetic energy of the system K.E = K.E₁ + K.E₂
K.E₁ = ½mv₁² = ½ * 9.11 *10⁻³¹ * (8.78*10⁷)²
k.e₁ = 3.511 * 10⁻¹⁵ J
k.e₂ = 1/2 mv₂² = 1/2 * 9.11*10⁻³¹ * (1.67*10⁸)²
k.e₂ = 1.27*10⁻¹⁴J
K.E = k.e₁ + k.e₂
K.E = 3.511*10⁻¹⁵ + 1.27*10⁻¹⁴
K.E = 1.6211*10⁻¹⁴J
1eV = 1.602 * 10⁻¹⁹J
xeV = 1.6211*10⁻¹⁴J
x = 101,192.23eV = 101.192keV
I think trace 1 is ac and trace 2 if dc but i’m not sure what will happen when a higher frequency is added?
Answer:
A) 1.9m/s
Explanation:
Use the equation v=d/t
The time is 10 seconds. The distance is more complicated because it’s a circle so u use the equation for circumference C=2•pi•r. So you just do the circumference over time and get the answer. Hope this helps
Astrology is not science, it bases itself on twelve zodiac signs, astronomy however studies many phenomena in space in order to figure out how we came to be
Answer:
the weight of alien is 200 newtons
Explanation:
The computation of the alien weight is shown below:
Given that
Acceleration = 20m/sec^2
And, the mass is 10 kg
So, the weight of alien is
= 20 × 10
= 200 newtons
hence, the weight of alien is 200 newtons