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ioda
3 years ago
7

Can anyone help with this physics question

Physics
1 answer:
Elza [17]3 years ago
7 0
I think trace 1 is ac and trace 2 if dc but i’m not sure what will happen when a higher frequency is added?
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A body with mass of 200 g is attached to the end of a spring that is stretched 20 cm by a force of 9 N. At time tequals0 the bod
11Alexandr11 [23.1K]

Answer:

X(t) = 13/13 cos(12t+α)

C =13/13

π/6 s

Explanation:

(A) A body with mass 200 g is attached to the end of a spring that is stretched 20 cm by a force of 9 N. At time t = 0 the body is pulled 1 m in to the right, stretching the spring, 3 set in motion with an initial velocity of 5 m/s to the left.  

(a) Find X(t) in the form c • cos(w_o*t— α)  

(b) Find the amplitude 3 Period of motion of the body 1  

mass: m = 200g =  0.200 kg  

displacement: ΔX = 20 cm =  0.20 m

Spring Constant: K =  9/0.20 = 45 N/m

IV:   X(0) = 1m V(0) = -5 m/s

Simple Harmonic Motion: c•cos(cosw_t— α) = X(t)  

Circular Frequency: w_o = √k/m= √36/(0.20) = 13 rad/s

X(0) = 1m =c_1

X'(0) = V(0) = c_2*w_o/w_o

        = -5/12 =   c_2

"radians Technically Unitless"  

Amplitude: c = √ci^2 + c^2 ==> √1^2 + (-5/12)^2 = 1 m =13/13 = c

X(t) = 13/13 cos(12t+α)

since, C>0 : damped forced vibration c_1>0, c_2>0

phase angle 2π+tan^-1(c_2/c_1)

                        =2π+tan^-1(-5/12/1)= 5.884

period: T =2π/w_o

                =π/6 s

6 0
4 years ago
what is the focalength of the combination of two thin renses of power -5D and -2D placeci in contact with each other?​
Ghella [55]

Answer:

f = - 0.143 m = - 14.3 cm

Explanation:

First, we will calculate the power of the combination of lenses:

P = P₁ + P₂

where,

P = Power of Combination = ?

P₁ = Power of first lens = - 5D

P₂ = Power of second lens = - 2D

Therefore,

P = - 5D - 2D

P = - 7D

Now, the focal length can be given as:

f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\

<u>f = - 0.143 m = - 14.3 cm</u>

Negative focal length indicates that combination will act as diverging lens.

6 0
3 years ago
A van of mass 2500kg travelling at a velocity of 12 m/s collides with a stationary car of mass 700kg. The vehicles move together
Fiesta28 [93]

Answer: 9.375m/s

Explanation: This is an inelastic collision, so the formula is mv1+mv2=(m1+m2)v-final. My work is a follows:

2500kg(12m/s) + 700kg(0m/s)=(2500kg+700kg)(v-final)

30,000kg(m/s)+0=3200kg(v-final)

30,000kg(m/s)/3200kg=9.375m/s

5 0
3 years ago
Cell with structures labeled A, B, and C
sveticcg [70]
The answer is A. :)
6 0
3 years ago
Read 2 more answers
Một con lắc lò xo dao động điều hoà theo phương thẳng đứng, trong quá trình dao động của vật lò xo có chiều dài biến thiên từ 20
san4es73 [151]

Answer:

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Explanation:

buang ka

6 0
3 years ago
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