All categories

4 years ago

1. {(0, 2), (4, 2), (3, 2), (5, 1), (6, 2)}

1 answer:

8 0

A) The domain of this relation would be 0,4,3,5, and 6. These are our possible x values for the function. Since this equation doesn't tell us to assume that it's a function then it's fine for us to list them separately.
B) The range of this function is 2 and 1. This is for the same reasons listed in A.
C) This can be a function because although it has the same y-values several times, the x values are always different. This would not be a linear function though, since the slope should be zero, and the value (5,1) would come off of the function y=2.

You might be interested in

Bob gets the following homework grades:

tankabanditka [31]

Step-by-step explanation:

for bob;

his grades = 2, 2, 2, 2, 2, 10, 10, 10, 10, 10.

total = 60

mean = total/n

= 60/10 = 6

meadian is the middle value in the set of scores. the numbers are even so =

2+10 / 2

median = 12/2 = 6

standard deviation using excel = 4.216

for tom

7, 7, 7, 7, 7, 7, 7, 7, 7, 7

total = 70

mean = 70/10 = 7

median = 7+7/2 = 14/2 = 7

standard deviation using excel = 0

for pat:

1, 1, 8, 8, 8, 8, 8, 8, 10, 10

total = 70

mean = 70/10 = 7

median = 8+8/2 = 16/2 = 8

standard deviation using excel = 3.265

4 0

3 years ago

1. javier worked the following hours in the month of october. what was the person increase from week 2 to week 4?

RSB [31]

You would have to subtract week 4 from week 2 to find the increase in hours so 24-18 is 6. Therefore the increase from week 2 to week 4 is 6.

4 0

3 years ago

Find the exact value

ivann1987 [24]

Answer:

Step-by-step explanation:

$cos~ \theta=\sqrt{1-sin^2 \theta} =\sqrt{1-(\frac{1}{2})^2 } =\frac{\sqrt{3} }{2} \\1+cos~\theta=2cos^2\frac{\theta}{2} \\1+\frac{\sqrt{3}}{2} =2~cos^2 \frac{\theta}{2} \\cos^2\frac{\theta}{2} =\frac{2+\sqrt{3}}{2 \times 2} \\cos \frac{\theta}{2} =\frac{\sqrt{2+\sqrt{3}}}{2} \\1-cos \theta=2 ~sin^2\frac{\theta}{2} \\1-\frac{\sqrt{3}}{2}=2~sin^2 \frac{\theta}{2} \\sin^2 \frac{\theta}{2} =\frac{2-\sqrt{3} }{2 \times 2} \\sin \frac{\theta}{2}=\frac{\sqrt{2-\sqrt{3} } }{2}$

as 0≤θ≤90

so θ/2 is also in 0≤θ≤90

hence sin θ/2 and cos θ/2 are positive.

3 0

3 years ago

Which represents the solution set of the inequality 5x-9<21

Tomtit [17]

Answer:

x < 6

Step-by-step explanation:

5x -9 < 21

then add 9 to both sides

5x< 30

divide by five

x<6

4 0

3 years ago

Can you help me with this question

kari74 [83]

Answer:

-1.67

Step-by-step explanation:

8 0

3 years ago