Answer:
The pressure after passing the valve is 23,8 [Kpa] ( 0,234 atm) and the pressure drop is about 1,53 [Kpa]
Explanation:
We need to use the formula of bernoulli, in the attached image we can see the fluid throw the pipe, we also can calculate the velocity inside the pipe using the flow rate and the cross sectional area.
For this case, we don't use the elevation difference and therefore those terms can be cancelled.
When the area has reduced the velocity of the fluid is increased but there is a drop pressure through the valve.
Answer:
greater than 0.10
Explanation:
The null hypothesis is:
The alternate hypotesis is:
Our test statistic is:
In which X is the statistic, is the mean,
is the standard deviation and n is the size of the sample.
We have that:
We are testing if X is greater than 0.45, so our pvalue is 1 subtracted by the pvalue of z = t = 0.45.
z = 0.45 has a pvalue of 0.6736
1 - 0.6735 = 0.3264
So our pvalue is 0.3264, which is greater than 0.10.
So the correct answer is:
greater than 0.10
Total displacement of the car: 405 m
Explanation:
The first part of the motion of the car is a uniformly accelerated motion, so we can use the suvat equation
where:
u = 0 is the initial velocity (the car starts from rest)
is the time elapsed in the 1st part
is the acceleration of the car in the 1st part
is the displacement of the car in the 1st part
Solving for ,
We can also find the velocity of the car after these 20 seconds using the equation:
Now we can find the distance covered by the car in the 2nd part, where it decelerates after having seen the tree limb on the road. We can do it by using the suvat equation:
where:
is the initial velocity at the beginning of the 2nd phase
is the final velocity (the car comes to a stop)
is the time elapsed in the 2nd phase
Substituting,
So, the total displacement of the car is
Learn more about accelerated motion:
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