A ball falling through the air has a mass, a density, a volume...it is facing air resistance and is being acted on by gravity...it is accelerating and gaining velocity...and it is increasing in kinetic energy.
I suppose out of all those the biggest thing the ball has in this case is ENERGY. There are two main types to focus on...
Kinetic Energy - The further the ball fall the more KE it has...until terminal velocity is reach, then KE would become constant.
Potential Energy - Conversely to that of KE, the further the ball falls the less PE it will have.
<em>Heat/Thermal Energy is technically also present due to the friction from the air resistance, but the transfer of energy between the air and ball is quite complex and not necessary important for basic physics.
</em>
The question itself seem kind of vague and open ended, but I could just be viewing it the wrong way.
Comment if you need more help!
Answer:
Magnitude of vector A = 0.904
Explanation:
Vector A , which is directed along an x axis, that is

Vector B , which has a magnitude of 5.5 m


The sum is a third vector that is directed along the y axis, with a magnitude that is 6.0 times that of vector A 
Comparing we will get

Substituting in 

So we have

Magnitude of vector A = 0.904
force is mass multiply by acceleration so it will be 150 multiply by 10 is 1500N
Answer:
hello your question is incomplete attached below is the missing part
answer : short period oscillations frequency = 0.063 rad / sec
phugoid oscillations natural frequency (
) = 4.27 rad/sec
Explanation:
first we have to state the general form of the equation
= 
where :


comparing the general form with the given equation
= 18.2329

hence the short period oscillation frequency (
) = 0.063 rad/sec
phugoid oscillations natural frequency (
) = 4.27 rad/sec
Answer:
Explanation:
E = σ/ε = (F/A) / (ΔL/L)
E = (mg/(πd²/4) / (ΔL/L)
E = (4mg/(πd²) / (ΔL/L)
E = 4Lmg/(πd²ΔL)
E = 4(30.0)(90)(9.8)/(π(0.01²)0.25)
E = 1.35 x 10⁹ Pa or 1.35 GPa