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mel-nik [20]
3 years ago
12

With the correct choice of acid, acid hydrolysis of ethanamide could produce A) ethanoic acid and ammonium chloride. B) ethanoic

acid and methylamine. C) ethanol and ammonia. D) acetaldehyde and ammonium hydroxide. E) formic acid and ethylamine

Chemistry
1 answer:
Stells [14]3 years ago
7 0

Answer:

A) Ethanoic acid and ammonium chloride.

Explanation:

Amides go through acid hydrolysis to produce carboxylic acid and ammonia by heating in aqueous acid. The acid hydrolysis reaction is produced through the <u>nucleophilic addition of water to the protonated amide</u>, then comes the transference of a proton from the oxygen to the nitrogen to make nitrogen a better leaving group, and finally, the subsequent elimination (see attachment).

In this case, the products formed with the reaction of ethanamide and aqueous HCl will be <u>ethanoic acid and ammonium chloride</u>.

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Research the compositions of Pennies. What was the composition of each of your Pennies prior to treatment
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Answer:

History of composition

Years Material Weight (grains)

1944–1946 gilding metal (95% copper, 5% zinc) 48 grains

1947–1962 bronze (95% copper, 5% tin and zinc) 48 grains

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October 1982 – present copper-plated zinc (97.5% zinc, 2.5% copper) 38.6 grains

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2 years ago
Briefly explain whether the following procedural errors would result in either an incorrectly high or incorrectly low calculated
seropon [69]
<span>A) This solution was not basic when it was heated in part 3. ( in part 3 i convertedCu(OH)2 to CuO).
Incorrectly low, because not all copper compounds will precipitate out

B) A slightly blue solution was decanted from Cu in part V. (in part 5 i reduced Cu(H20)6 ions with zink)
Incorrectly low, because some copper were thrown away

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3 years ago
A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) &lt;---&gt; N2(g) 3H2(g) At equilibrium, it was fou
Softa [21]

Answer:

Kc for this equilibrium is 2.30*10⁻⁶

Explanation:

Equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction and the concentrations of reactants and products are held constant.

Being:

aA + bB ⇔ cC + dD

the equilibrium constant Kc is defined as:

Kc=\frac{[C]^{c}*[D]^{d}  }{[A]^{a} *[B]^{b} }

In other words, the constant Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients. Kc is constant for a given temperature, that is to say that as the reaction temperature varies, its value varies.

In this case, being:

2 NH₃(g) ⇔ N₂(g) + 3 H₂(g)

the equilibrium constant Kc is:

Kc=\frac{[N_{2} ]*[H_{2} ]^{3}  }{[NH_{3} ]^{2} }

Being:

  • [N₂]= 0.0551 M
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and replacing:

Kc=\frac{0.0551*0.0183^{3}  }{0.383^{2} }

you get:

Kc= 2.30*10⁻⁶

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Answer:

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Answer:

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Explanation:

Ionization energy trend along group:

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As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

Ionization energy trend along period:

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3 years ago
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