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3 years ago

The Concentration of C6H12O6 May be represented as?

Chemistry

2 answers:

Amiraneli [1.4K]3 years ago

6 0

Answer:

A 12 oz Coca Cola contains 39g of sugar or C6H12O6.

To calculate for the molarity of sugar in the soda, convert 39 grams of sugar to moles sugar:

39g/ 180.16 g/mol = 0.216 mol sugar

then, convert 12 oz to L:

12oz / (1oz/0.02957L) = 0.35484 L

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n

= 0.216 mol sugar / 0.35484 L

= 0.609 M

Explanation:

spin [16.1K]3 years ago

3 0

Answer:

Explanation:

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n

= 0.216 mol sugar / 0.35484 L

= 0.609 M

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2 years ago

A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h

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Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

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1) Molarity of 0.250 L HCl solution : 0.0328 M

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Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}$

Moles of NaOH in 0.100 L solution = 0.00245 moles

3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles = 0.00575 moles

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0.0164 molar concentration of hydrochloric acid in the resulting solution.

3 0

3 years ago