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Savatey [412]
3 years ago
15

What is the difference between inert and stable?

Chemistry
1 answer:
Katena32 [7]3 years ago
7 0
Inert means that the substance did not have a tendency to react at all, while stable means that the substance has reached a chemical state in which it is not likely to react. Stability is easier to overcome than inertness.
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Someone please help me with number 5. no idea what it is.
KATRIN_1 [288]
Answer is Sodium Hydroxide.
5 0
3 years ago
What is the chemical formula for methane?
aleksandr82 [10.1K]
The chemical formula for methane is CH4

6 0
3 years ago
How many seconds does it take a race horse to run six furlongs at 40.7 miles per hour if: I furlong = 40 rods; 5.5 yards = 1 rod
lana [24]

Distance traveled by the race horse=6 furlongs

Converting the distance from furlongs to rods: 40 rods =1 furlong

6 furlongs*\frac{40rods}{1furlong} =240rods

Converting the distance from rods to yards, feet and miles: 5.5 yards = 1 rod, 3foot =1 yard, 1 mile = 5280 feet.

240rods*\frac{5.5yards}{1rod}*\frac{3foot}{1yard}*\frac{1mi}{5280feet}=0.75mi

The given speed of race horse = 40.7mi/hr

Calculating the time required:

0.75mi*\frac{1hr}{40.7mi}*\frac{60min}{1hr}*\frac{60s}{1min}= 66.34s

Therefore, 66.34 s is required for a race horse to run six furlongs at 40.7 miles per hour.

8 0
3 years ago
N204(0) + 2NO2(g)
user100 [1]

setup 1 : to the right

setup 2 : equilibrium

setup 3 : to the left

<h3>Further explanation</h3>

The reaction quotient (Q) : determine a reaction has reached equilibrium

For reaction :

aA+bB⇔cC+dD

\tt Q=\dfrac{C]^c[D]^d}{[A]^a[B]^b}

Comparing Q with K( the equilibrium constant) :

K is the product of ions in an equilibrium saturated state  

Q is the product of the ion ions from the reacting substance  

Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)

Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium

Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)

Keq = 6.16 x 10⁻³

Q for reaction N₂O₄(0) ⇒ 2NO₂(g)

\tt Q=\dfrac{[NO_2]^2}{[N_2O_4]}

Setup 1 :

\tt Q=\dfrac{0.0064^2}{0.098}=0.000418=4.18\times 10^{-4}

Q<K⇒The reaction moved to the right (products)

Setup 2 :

\tt Q=\dfrac{0.0304^2}{0.15}=0.00616=6.16\times 10^{-3}

Q=K⇒the system at equilibrium

Setup 3 :

\tt Q=\dfrac{0.230^2}{0.420}=0.126

Q>K⇒The reaction moved to the left (reactants)

8 0
3 years ago
Read 2 more answers
Please help! need the answer fast. Determine the amplitudes and the wave-lengths of each of the three waves.
Diano4ka-milaya [45]
A amplitude = 0.50 m and wave-length = 1.0 m

B amplitude = 0.40 m and wave-length = 2.0 m

C amplitude = 0.60 m and wave-length = 2.0 m
3 0
3 years ago
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