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3 years ago

What is the difference between inert and stable?

1 answer:

7 0

Inert means that the substance did not have a tendency to react at all, while stable means that the substance has reached a chemical state in which it is not likely to react. Stability is easier to overcome than inertness.

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Mars2501 [29]

Are spotted cats cuter than solid-colored cats?

4 0

3 years ago

Use the periodic table to calculate the percent composition of hydrogen in hexane.

valina [46]

Answer:

A)16.3% (Hexane's formula is C6H14)

3 0

2 years ago

Calculate the mass of khc8h4o4 that reacts with 15 ml of the naoh solution

dlinn [17]

The balanced chemical reaction would be:

KHC8H4O4<span> (aq) + </span>NaOH<span> (aq) → NaKC8H4O4 (aq) + H2O.

The concentration of the NaOH is equal 0.1 M. We use this and the volume given above to determine the mass of KH</span>C8H4O4. We do as follows:

0.1 mol / L NaOH (.015 L) ( 1 mol KHC8H4O4 / 1 mol NaOH) (204 g / 1 mol) = 0.306 g KHC8H4O4

6 0

3 years ago

Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts

SOVA2 [1]

Answer:

$\boxed{\text{Mg is the limiting reactant}}$

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble the data in one place.

2Mg + O₂ ⟶ 2MgO

n/mol: 2 5

Calculate the moles of MgO we can obtain from each reactant.

From Mg:

The molar ratio of MgO:Mg is 2:2

$\text{Moles of MgO} = \text{2 mol Mg} \times \dfrac{\text{2 mol MgO}}{\text{2 mol Mg}} = \text{2 mol MgO}$

From O₂:

The molar ratio of MgO:O₂ is 2:1.

$\text{Moles of MgO} = \text{5 mol O}_{2} \times \dfrac{\text{2 mol MgO}}{\text{1 mol O}_{2}} = \text{10 mol MgO}\\\\\boxed{\textbf{Mg is the limiting reactant}} \text{ because it gives the smaller amount of MgO}$

6 0

3 years ago

Given a 0.200 M solution of anserine at its isoelectric point and ready access to 0.100 M HCl, 0.100 M NaOH and distilled water,

vekshin1

Solution :

Given :

Amount of anserine solution = 0.200 M

pH value is = 7.20

Preparation of 0.04 M solution of anserine from the 0.2 M solution.

0.2 M x $x$ = 0.04 M x 1000 ml

$x$ = 200 ml

So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.

0.1 M x $x$ = 0.04 x 1000 ml

$x$ = 400 ml

Therefore, 400 ml of HCl is needed.

6 0

2 years ago