1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Semmy [17]
3 years ago
7

What does viscosity describe?

Chemistry
2 answers:
kakasveta [241]3 years ago
5 0

: a fluid's resistance to flowing

~Sarah Robinsen

pychu [463]3 years ago
4 0
I believe the answer to this one...........is D
You might be interested in
Explain the difference in the boiling point of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity an
Len [333]
The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.

As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.

The Interactions found in these compounds are London Dispersion Forces.

And among several factors at which London Dispersion Forces depends, one is the size of molecule.

Size of Molecule:
                          There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.
6 0
3 years ago
Which scenario best describes a relationship of parasitsm
saveliy_v [14]
Parasitism... basically a tick and a dog. The dog is the host, which is harmed by the tick.
3 0
3 years ago
Some one please help me ​
Norma-Jean [14]

Answer:

C.4

Explanation:

6 0
3 years ago
Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. An excess of AgNO3 is present.
sweet [91]
Toichiometry time! Remember to look at the equation for your molar ratios in other problems.
31.75 g Cu | 1 mol Cu | 2 mol Ag | 107.9 g Ag         6851.65⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻   →   ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻  = 107.9 g Ag       ∅        | 63.5 g Cu | 1 mol Cu | 1 mol Ag              63.5

There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.

3 0
3 years ago
Read 2 more answers
Concerning the 10.0 mL of 0.50 M NaCl 100 mL of soltion:Does the dilution change the concentration
disa [49]
The answer is affirmative because <span>dilutions give you a weaker Molarity 
Plase see this in the dilution formula that follows:

C1V1 = C2V2 
(0.50M) (10.00ml) = (C2) (100ml) 
C2 = 0.050 M 
10X's weaker
</span>Hope this helps a lot 
6 0
3 years ago
Read 2 more answers
Other questions:
  • I can't find the density of this question I need help
    13·1 answer
  • Which form of bonding holds cesium chloride (CsCl) together?
    7·1 answer
  • Which prototype is the most cost- and time-effective solution? The Rockets First company needs to hire an engineer to develop a
    14·2 answers
  • Acts as the digestive system inside a cell. It helps to break down old or unneeded parts of the cell, and substances that have b
    5·1 answer
  • ANSWER THIS QUESTION<br><br><br><br><br><br><br><br><br><br> :)))
    5·1 answer
  • What do you know about magnets?
    15·1 answer
  • Coach Scott hits a baseball with his bat to help his players with fielding
    7·1 answer
  • Can someone please describe what they’re seeing in this picture?
    10·1 answer
  • 1. Do you think water molecules speed up or slow down<br> when they are heated? *
    8·1 answer
  • How the atoms in diagram A differ from those in diagram D
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!