Answer:
The new volume is 7.27 L
Explanation:
Step 1: Data given
The initial volume of the balloon = 7.0 L
The pressure = 765 mmHg = 765/760 atm = 1.00658 atm
The pressure drops to 737 mmHg = 737/ 760 atm = 0.969737
The temperature remains constant
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒with P1 = the initial pressure in the balloon = 765 mmHg
⇒with V1 = the initial volume = 7.0L
⇒with P2 = the decreased pressure = 737 mmHg
⇒with V2 = the new volume = TO BE DETERMINED
765 mmHg * 7.0 L = 737 mmHG * V2
V2 = (765 mmHG * 7.0 L) / 737 mmHG
V2 = 7.27 L
The new volume is 7.27 L
It’s Nitrogen (N) with a -3 charge
Like all cells without a nucleus it will not carry DNA thus the inability to reproduce its life span will be short
First, we write the balanced equation for this reaction:
2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂
From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:
Moles = volume (in L) * molarity
We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:
M₁V₁ = 2M₂V₂
V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L
The volume required is 173.6 mL