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VARVARA [1.3K]
3 years ago
9

A plane flies 1,480 miles in 4 hours, with the wind. On its return trip, it took 5 hours flying against the same wind to go 1,15

0 miles. How fast would the plane have flown without any wind? Type in your numerical answer only; do not type any words or letters with your answer.
Physics
1 answer:
Katarina [22]3 years ago
3 0

Answer:300 mi/hr

Explanation:

Given

Plane Flies 1480 miles in 4 hr with the wind

While returning it took 5 hr to cover 1150 miles against the wind

Let v and v_0 be the absolute speed of Plane and wind

Thus during with the flow of wind

time=\frac{Distance}{Speed}

\frac{1480}{v+v_0}=4

370=v+v_0   ------------1

During return trip wind speed oppose Plane thus

\frac{1150}{v-v_0}=5

230=v-v_0    ----------2

adding 1 & 2 we get

600=2v+v_0-v_0

v=300 mph

Thus Speed of plane without wind is 300 mi/hr

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The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

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Then, the horizontal momentum is:

15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
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I hope it helps you!            

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