What is 5C in physics
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Answer:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
Explanation:
Answer:
Work done is 50.4J.
Explanation:
The work done by the student in lifting the book 1.2 meters vertically is
When the student begins to walk horizontally, the net force on the book is zero <em>(gravity is pulling it down, the student is lifting it up)</em>. Thus, although the student is displacing the book horizontally, but because no force is exerted on it, the work done is zero.