Dispersion im pretty sure
Answer: B) 0.00337 m3.
Explanation:
Given data:
Mass of the ball = 10kg
Weight of the ball in air = 98N
Weight of the ball in water = 65N
Solution:
To get the Volume of the ball when submerged in water, we divide the weight of the ball in water with the difference in apparent weight by 9.8m/s^2.
= 98 - 65 / 9.8
= 33 / 9.8
= 3.37kg
The volume of the ball is 3.37kg
The density of water is 1kg per Liter.
So 3.37 kg of water would have a volume of 3.37 Liters.
Therefore the ball would have a volume of 3.37 Liters (or 0.00337 cubic meters).
Answer:
I believe it's the first option
Answer:
18 km
Explanation:
Convert km/h to m/s:
120 km/h × (1000 m/km) × (1 h / 3600 s) = 33.3 m/s
The time it takes the bomb to travel the 2000 meters is:
2000 m / (33.3 m/s) = 60 s
So it takes 60 seconds for the bomb to fall. The distance it fell is therefore:
Δy = v₀ᵧ t + ½ aᵧ t²
Δy = (0 m/s) (60 s) + ½ (10 m/s²) (60 s)²
Δy = 18,000 m
Δy = 18 km
Answer:
Assume that the ball undergoes motion along a straight line. ... F = m A Force = (mass) x (acceleration) The question tells you the mass and the acceleration. All YOU have to do is take the numbers and pluggum into Newton's 2nd law. F = m A = (0.75 kg) (25 m/s²) = (0.75 x 25) kg-m/s² = 18.75 Newtons .
Explanation:
i looked it up ok
