4. a poor insulator
If rest other things are kept constant or unchanged then a good conductor can be termed as a poor insulator.
Answer:
a) K = 2/3 π G m ρ R₁³ / R₂
, b) U = - G m M / r
Explanation:
The law of universal gravitation is
F = G m M / r²
Part A
Let's use Newton's second law
F = m a
The acceleration is centripetal
a = v² / R₂
G m M / R₂² = m v² / R₂
v² = G M / R₂
They give us the density of the planet
ρ = M / V
V = 4/3 π R₁³
M = ρ V
M = ρ 4/3 π R₁³
v² = 4/3 π G ρ R₁³ / R₂
K = ½ m v²
K = ½ m (4/3 π G ρ R₁³ / R₂)
K = 2/3 π G m ρ R₁³ / R₂
Part B
Potential energy and strength are related
F = - dU / dr
∫ dU = - ∫ F. dr
The force was directed towards the center and the vector r outwards therefore there is an angle of 180º between the two cos 180 = -1
U- U₀ = G m M ∫ dr / r²
U - U₀ = G m M (- r⁻¹)
We evaluate for
U - U₀ = -G m M (1 /
- 1 /
)
They indicate that for ri = ∞ U₀ = 0
U = - G m M / r
The use of drugs to treat disease is called medication
submarinismo is scuba diving but Bueco is dive
In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.
The matter in gaseous state can be expanded to occupy the volumes of the container.
<h3>
Volume of each of the container</h3>
The volume of each of the container is calculated as follows;
<h3>Volume of the rectangular container</h3>
V = 5 in x 6 in x 3 in
V = 90 in³
<h3>Volume of the cylindrical container</h3>
V = πr²h
V = (π)(2.5 in)²(8 in)
V = 157.1 in³
<h3>Volume of the matter</h3>
Vm = 3 in x 4 in x 5 in
Vm = 60 in³
<h3>Matter in solid and liquid state</h3>
Matter has fixed volume in solid and liquid state.
In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.
<h3>Matter in gaseous state</h3>
Matter has no definite volume in gaseous state.
The matter in gaseous state can be expanded to occupy the volumes of the container.
Learn more about states of matter here:
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