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nalin [4]
3 years ago
14

How are valence electrons different from other electrons

Chemistry
1 answer:
erik [133]3 years ago
6 0
They are on the last level of the atoms
You might be interested in
Which species acts exclusively as spectator ions in this reaction
adelina 88 [10]

Answer:

K^+ and NO3^-

Explanation:

In a balanced ionic equation, we usually see the species that react to yield the main product in the reaction.

Consider the reaction;

Pb(NO3)2(aq) +2 KI(aq) -------> PbI2(s) + 2KNO3(aq)

The main product in this reaction is PbI2. Hence the balanced ionic equation is;

Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)

Notice that K^+ and NO3^- did not participate in this reaction. All ions that are part of the molecular equation but do not participate in the ionic reaction equation are called spectator ions. Hence K^+ and NO3^- are spectator ions in this reaction as can be seen clearly above.

4 0
3 years ago
Question 11 (10 points)
andrey2020 [161]

Answer:

The correct answer is option a.

Explanation:

When aluminum hydroxide reacts with of nitrous acid it gives of aluminum nitrite and of water.

Al(OH)_3+3HNO_2\rightarrow Al(NO_2)_3+3H_2O

According to above reaction ,when 1 mole of aluminum hydroxide reacts with 3 moles of nitrous acid it gives 1 mole of aluminum nitrite and 3 moles of water.

Hence, the correct answer is option a.

4 0
3 years ago
Adding more than one equivalent of HCl to pent-1-yne will lead to which product:______.
Ket [755]

Answer:

c. 2,2-dichloropentane.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly draw the structure of the reactant, pent-1-yne:

CH\equiv C-CH_2-CH_2-CH_2

Now, we infer the halogen is added to the carbon atom with the most carbon atoms next to it, in this case, carbon #2, in order to write the following product:

CH\equiv C-CH_2-CH_2-CH_2+2HCl\rightarrow CH_3- CCl_2-CH_2-CH_2-CH_2

Whose name is 2,2-dichloropentane.

Regards!

8 0
2 years ago
If you have 222 g of radioisotope with a half-life of 5 days, how much isotope would remain after 15 days?
Dima020 [189]
If the half life is 5 days, you would have to divide 222 by 2 3 times.
so 222/2 =111g
111/2 = 55.5g
55.5/2 = 27.75g

after four half life the mass would be
27.75/2
13.875g

the percent would be
13.875/222
= 6.25%
7 0
3 years ago
Which of the following would form a nonelectrolyte solution in water? A. KCl B. NaNO3 C. C6H12O6 D. Cu2SO4
ss7ja [257]
<span>C. C6H12O6

</span>This compound is covalent, and all salts are ionic compounds.
3 0
3 years ago
Read 2 more answers
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