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3 years ago

What is the wavelength of a radio wave with a frequency of 1x10^8 Hz?

Chemistry

1 answer:

lbvjy [14]3 years ago

5 0

Answer:

The wavelength of radio wave is 3m

Explanation:

speed of r.w (v) = 3 × 10⁸ m/s

frequency (f) = 1 × 10⁸ Hz

wavelength (λ) = ?

$v = f λ$

λ = v/f

= (3 × 10⁸) ÷ (1 × 10⁸)

= 3m

(Correct me if i am wrong)

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Which of the following is true about chemical reactions. A. they are accompanied by changes in energy. B. they form new substanc

Ilia_Sergeevich [38]

The correct answer should be option C. hope this helps

7 0

3 years ago

Iron has a density of 7.86 g/cm3 (1 cm3=1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 3.26 kg . Note t

Mkey [24]

$d=7,86\frac{g}{cm^{3}}=7,86\frac{0,001kg}{0,01dL}=0,786\frac{kg}{dL}\\
m=3,26kg\\\\\\
d=\frac{m}{V} \ \ \ \ \Rightarrow \ \ \ \ V=\frac{m}{d}=\frac{3,26kg}{0,786\frac{kg}{dL}}\approx4,15dL$

7 0

3 years ago

Consider a solution that is 0.05 M HCl. Your goal is to neutralize 1 L of this solution (i.e. bring the pH to 7). You also have

Ilia_Sergeevich [38]

Answer:

The volume of NaOH required is - 0.01 L

Explanation:

At equivalence point ,

Moles of $HCl$ = Moles of NaOH

Considering :-

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

Given that:

$Molarity_{NaOH}=5\ M$

$Volume_{NaOH}=?\ L$

$Volume_{HCl}=1\ L$

$Molarity_{HCl}=0.05\ M$

So,

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

$0.05\times 1=5\times Volume_{NaOH}$

$Volume_{NaOH}=\frac{0.05\times 1}{5}=0.01\ L$

<u>The volume of NaOH required is - 0.01 L</u>

3 0

3 years ago

Calculate the solubility at 25°C of CuBr in pure water and in a 0.0120M CoBr2 solution. You'll find Ksp data in the ALEKS Data t

iragen [17]

Answer:

S = 7.9 × 10⁻⁵ M

S' = 2.6 × 10⁻⁷ M

Explanation:

To calculate the solubility of CuBr in pure water (S) we will use an ICE Chart. We identify 3 stages (Initial-Change-Equilibrium) and complete each row with the concentration or change in concentration. Let's consider the solution of CuBr.

CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)

I 0 0

C +S +S

E S S

The solubility product (Ksp) is:

Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S²

S = 7.9 × 10⁻⁵ M

<u>Solubility in 0.0120 M CoBr₂ (S')</u>

First, we will consider the ionization of CoBr₂, a strong electrolyte.

CoBr₂(aq) → Co²⁺(aq) + 2 Br⁻(aq)

1 mole of CoBr₂ produces 2 moles of Br⁻. Then, the concentration of Br⁻ will be 2 × 0.0120 M = 0.0240 M.

Then,

CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)

I 0 0.0240

C +S' +S'

E S' 0.0240 + S'

Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S' . (0.0240 + S')

In the term (0.0240 + S'), S' is very small so we can neglect it to simplify the calculations.

S' = 2.6 × 10⁻⁷ M

8 0

2 years ago

890J of heat are applied to a piece of aluminum, causing a 4.6°C increase in its temperature. The specific heat of aluminum is 0

Semmy [17]

Answer:

The answer would be C 214g

Explanation:

890j of heat causes 4.6°c increase in temperature

specific heat of aluminium after is o.9022 j /g°c

now by using the formula .The mass of aluminium would be c that is 214 g

7 0

3 years ago