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mash [69]
4 years ago
8

Consider a loop of wire with a resistor. in the same plane, (with switch s closed) a long wire has a current i flowing from righ

t to left. bancroft (acb3943) – hw06 – lai – (55310) 3 r i s if switch s is open for a long period of time, and then suddenly closed, what is the direction of the induced current through r as the current i rapidly increases? 1. the current flows left to right through r. 2. the current flows right to left through r. 3. there is no current flow.
Physics
1 answer:
sp2606 [1]4 years ago
6 0

Answer:

1) The current flows left to right through r

Explanation:

When the switch S is suddenly closed, current begins to flow in the wire, then a magnetic field is created in the wire due to this flow of current. The magnetic field flows out of the page right to left.

A current is induced in the wire due to the magnetic field, this induced current  , according to lenz's law, opposes the magnetic field. Therefore, this induced current causes the magnetic field to move into the page which implies that the current will flow from left to right in r.

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The relatively small, rocky bodies generally found orbiting between mars and jupiter are known as _____. meteoroids satellites c
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6 0
3 years ago
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Which of the following is NOT a geological event caused by the movement of tectonic plates?
photoshop1234 [79]
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6 0
3 years ago
What is the length a rubberband was stretched if it has a spring constant of 5700N/m and is currently holding 8600J OF POTENTIAL
lozanna [386]

Answer:

\displaystyle \Delta x=1.74\ m

Explanation:

<u>Elastic Potential Energy </u>

Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.

\displaystyle PE = \frac{1}{2}k(\Delta x)^2

Given a rubber band of a spring constant of k=5700 N/m that is holding potential energy of PE=8600 J, it's required to find the change of length under these conditions.

Solving for Δx:

\displaystyle \Delta x=\swrt{\frac{2PE}{k}}

Substituting:

\displaystyle \Delta x=\sqrt{\frac{2*8600}{5700}}

Calculating:

\displaystyle \Delta x=\sqrt{3.0175}

\boxed{\displaystyle \Delta x=1.74\ m}

6 0
3 years ago
A bullet fired vertically at a velocity of 36m/s .after 45 the bullet hit the top of a bulid how height is a bulid?​
zzz [600]

Answer:

The height of the building is 8,302.5 m

Explanation:

Given;

velocity of the projectile, u = 36 m/s

time of motion, t = 45 s

Let the upward direction of the bullet be negative,

The height of the building is calculated as;

h = ut - \frac{1}{2} gt^2\\\\h = (36\times 45) - (\frac{1}{2} \times 9.8 \times 45^2)\\\\h = 1620 - 9922.5\\\\h = -8,302.5 \ m\\\\The \ height \ of \ the \ building \ is \ 8,302.5  \ m

3 0
3 years ago
6) Set the battery to a value between 0.0 V and 1.5 V. Now drag the voltage meter toward the capacitor and move the red and blac
KIM [24]

Answer:

A) 1.5 v

B) Top plate is at higher voltage than the bottom plate

Explanation:

Battery value set between 0.0 V and 1.5 V

a) The potential difference between the plates

Δ V = V1( potential at top plate) - V2( potential at lower plate )

potential at top plate = 1.5 V

potential at lower plate = 0.0 V

hence potential difference = 1.5 V

b ) The top plate is always connected to the positive terminal of the DC source ( which is at a higher potential )while the bottom plate is connected to the negative terminal of the DC source ( which is at a lower potential )

hence the Top plate is at higher voltage than the bottom plate

7 0
3 years ago
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