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3 years ago

11

The center on a high school basketball team wants to increase the maximum height of his jump. What statement correctly describes

how he could achieve this goal?

2 answers:

Katen [24]3 years ago

8 0

Jumping with more acceleration

Georgia [21]3 years ago

7 0

Answer:

Explanation:

D) Jumping with greater initial velocity would increase the height of his jump.

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Please help The position of masses 4kg, 6kg, 7kg, 10kg, 2kg, and 12kg are (-1,1), (4,2), (-3,-2), (5,-4), (-2,4) and (3,-5) resp

Sophie [7]

Answer:

(1.9756, -2.1951)

Explanation:

The center of mass equation is: $x_{cm}$ = $\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}$ , where m represents the masses and x represents the position.

In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.

<u>x-values:</u>

<u /> $x_{cm}$ = $\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}$ = $\frac{4(-1)+6(4)+7(-3)+10(5)+2(-2)+12(3)}{4+6+7+10+2+12}$ = $\frac{(-4)+(24)+(-21)+(50)+(-4)+(36)}{41}$ = $\frac{81}{41}$ = 1.9756

<u>y-values:</u>

<u /> $y_{cm}$ = $\frac{m_{1}y_{1} + m_{2}y_{2} + m_{3}y_{3} + m_{4}y_{4} + m_{5}y_{5} + m_{6}y_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}$ = $\frac{4(1)+6(2)+7(-2)+10(-4)+2(4)+12(-5)}{4+6+7+10+2+12}$ = $\frac{(4)+(12)+(-14)+(-40)+(8)+(-60)}{41}$ = $\frac{-90}{41}$ = -2.1951

<u>center of mass:</u>

(1.9756, -2.1951)

6 0

3 years ago

Waves can carry either ____ or __________ energy?

Oksanka [162]

Mechanical or Electromagnetic

3 0

2 years ago

Read 2 more answers

a transformer has 1,400 turns in the primary coil and 100 turns in the secondary coil. if the primary coil is connected to a 120

harkovskaia [24]

0.56 A is the current of the secondary coil.

transformer is the device that transfer electric energy from one AC circuit to another.

we know that ;

I ∝ 1/n;

where I IS CURRENT and n is NUMBER OF TURNS.

(I) secondary = X A

(n) secondary = 100

(I) primary = 0.04 A

(n) primary = 1400

USING THIS-----> I ∝ 1/n;

=>

0.04 A/X A =100/1400

=>X=0.56 A

as the current in the transformer is inversely proportional to the number of turns so 0.56 A is the current in the secondary coil.

learn more about transformers-

brainly.com/question/26991007

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4 0

1 year ago

April stands on a flat surface . If she has a mass of 72 what is the nirmal force acting on her

gayaneshka [121]

The normal force acting on April as she stands on a flat surface is 705.6 N.

Normal force of the girl

Fₙ = mg

where;

Fₙ is the normal force of the girl
m is mass of the girl
g is acceleration due to gravity

Fₙ = 72 x 9.8

Fₙ = 705.6 N

Thus, the normal force acting on April as she stands on a flat surface is 705.6 N.

Learn more about normal force here: brainly.com/question/14486416

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7 0

2 years ago

Consider a spherical planet of uniform density rho. The distance from the planet's center to its surface (i.e., the planet's rad

alisha [4.7K]

Answer:

a) $g(r) = 4\pi \cdot G \cdot \rho\cdot r$ , b) $g = 4\pi \cdot G \cdot \rho\cdot r_{P}$

Explanation:

a) The acceleration due to gravity inside the planet is:

$dg = G\cdot \frac{\rho \cdot dV}{r^{2}}$

$dg = G\cdot \frac{\rho \cdot dV}{r^{2}}$

$dg = G\cdot \frac{4\pi\cdot \rho \cdot r^{2}\,dr}{r^{2}}$

$dg = 4\pi\cdot G\cdot \rho \,dr$

$g(r) = 4\pi \cdot G \cdot \rho\cdot r$

b) The acceleration at the surface of the planet is:

$g = 4\pi \cdot G \cdot \rho\cdot r_{P}$

5 0

3 years ago