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jok3333 [9.3K]
3 years ago
9

Devonte pushes a wheelbarrow with 830 W of power. How much work is required to get the wheelbarrow across the yard in 11 s? Roun

d your answer to two significant figures.
Physics
2 answers:
zaharov [31]3 years ago
8 0
9,100 is the answer if you do the work so i failed for yall you welcome
Maslowich3 years ago
6 0

Answer: To get the wheelbarrow across the yard in 11 s Is required 9,100 J of work.

Explanation:

Hi, to solve this problem we have to apply the formula:

Power (w) = work (J) / time (sec)

So, replacing the variables with the values given:

830 w = work / 11sec

Isolating work we have:

830 w / 11 sec = work

Work = 9,130 J  = 9,100 j (rounded to two significant figures)

To get the wheelbarrow across the yard in 11 s Is required 9,100 J of work.

Feel free to ask for more if it´s necessary or if you did not understand something.

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Starting from rest, a person runs with a constant acceleration, traveling 40 meters in 10 seconds. What is their final velocity?
Assoli18 [71]

Answer:

Final velocity v = 8.944 m/sec

Explanation:

We have given distance S = 40 meters

Time t = 10 sec

As it starts from rest so initial velocity u = 0

From second equation of motion s=ut+\frac{1}{2}at^2

40=0\times 10+\frac{1}{2}a10^2

a=0.8944m/sec^2

Now from first equation of motion v=u+at, here v is final velocity, u is initial velocity, a is acceleration and t is time

So v=u+at=0+0.8944\times 10=8.944m/sec

6 0
3 years ago
What are atoms and molecules constantly doing?
Alexus [3.1K]

A. molecules are CONSTANTLY moving.

7 0
3 years ago
Read 2 more answers
A pendulum clock gives correct time at 20°c how many sec/day will it gain or loose when the temperature fall to 5°c? cofficient
rewona [7]

Answer:

129.6 seconds

Explanation:

Given that :

α = 0.0002°c-1​

θ1 = 20°C

θ2 = 5°C

Time t = one day ; Converting to seconds ; number of seconds in a day ; (24 * 60 * 60) = 86400 seconds

Let dT= change in time

Using the relation :

dT = 0.5* α * dθ * t

dθ = (20 - 5) = 15°C

dT = 0.5 * 0.0002 * 15 * 86400

dT = 129.6 seconds

5 0
3 years ago
A 280-m-wide river flows due east at a uniform speed of 4.7m/s. A boat with a speed of 7.1m/s relative to the water leaves the s
tamaranim1 [39]

Answer:

(a) The speed is 7.96 m/s

(b) The direction is 76 degree from positive X axis in counter clockwise direction.  

Explanation:

Width of river = 280 m

speed of river, vR = 4.7 m/s towards east

speed of boat with respect to water, v(B,R) = 7.1 m/s at 26 degree west of north

vR = 4.7 i \\\\v(B,R) = 7.1 (- sin 26 i + cos 26 j) = - 3.1 i + 6.4 j

(a) The velocity of boat with respect to ground is

\overrightarrow{v}_{(B,R)}=\overrightarrow{v}_{(B,G)}-\overrightarrow{v}_{(R,G)}\\\\- 3.1 \widehat{i} +6.4 \widehat{j}=\overrightarrow{v}_{(B,G)} - 4.7 \widehat{i}\\\\\overrightarrow{v}_{(B,G)} = 1.6 \widehat{i} + 6.4 \widehat{j}\\\\{v}_{(B,G)} = \sqrt{1.6^2 + 6.4^2}=6.96 m/s

(b) The direction is given  by

tan\theta = \frac{6.4}{1.6} =4\\\\\theta = 76^o

7 0
2 years ago
I WILL MAKE U BRAINLIEST PLEASE ANSWER !!!!!!!!
Nesterboy [21]

Answer:

125÷2= 62.5 is your average speed. If the train was resting it's not moving your going nowhere . If the train is traveling at constant speed in a straight line it's speed will increase going through mountains will slow it down. if the train is coming to a braking force its speed will decrease

3 0
2 years ago
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