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jok3333 [9.3K]
3 years ago
9

Devonte pushes a wheelbarrow with 830 W of power. How much work is required to get the wheelbarrow across the yard in 11 s? Roun

d your answer to two significant figures.
Physics
2 answers:
zaharov [31]3 years ago
8 0
9,100 is the answer if you do the work so i failed for yall you welcome
Maslowich3 years ago
6 0

Answer: To get the wheelbarrow across the yard in 11 s Is required 9,100 J of work.

Explanation:

Hi, to solve this problem we have to apply the formula:

Power (w) = work (J) / time (sec)

So, replacing the variables with the values given:

830 w = work / 11sec

Isolating work we have:

830 w / 11 sec = work

Work = 9,130 J  = 9,100 j (rounded to two significant figures)

To get the wheelbarrow across the yard in 11 s Is required 9,100 J of work.

Feel free to ask for more if it´s necessary or if you did not understand something.

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Answer:

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Explanation:

a)

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b)

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

c)

We now need the time at which y(t') = -64 ft

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By means of the quadratic formula, we find that

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Explanation:

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When light is reflected by a mirror, the angle of incidence is always A. equal to the angle of reflection. B. less than the angl
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Answer:

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It is given that,

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