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Makovka662 [10]
3 years ago
6

What volume of beaker contains exactly 2.23x10^-2 mol of nitrogen gas at STP?

Chemistry
1 answer:
nikklg [1K]3 years ago
4 0

Answer:

V = 0.5 L

Explanation:

Given data:

Moles of nitrogen = 2.23×10⁻² mol (0.0223 mol)

Temperature = 273 K

Pressure = 1 atm

Volume = ?

Solution:

PV = nRT

V = nRT / P

V = 0.0223 mol × 0.0821 atm. mol⁻¹. L . k⁻¹ × 273 K / 1 atm

V = 0.5 L

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Answer:

The answer to your question is below

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