If you mix salt sand and sugar with water what will the mixture be a solution because both sugar and salt can be diluted until the saturation point
Answer:
[KI] = 0.17 M
Explanation:
We determine the moles of solute:
Mass / Molar mass → 4.73 g / 166 g/mol = 0.0285 moles
Molarity (mol/L) is defined as moles of solute in 1L of solution
It is a sort of concentration
M = 0.0285 mol / 0.169L = 0.17 M
Instead of making the division (mol/L), we can also try this rule of three:
In 0.169 L we have 0.0285 moles of solute
in 1 L we must have ___ (1 . 0.0285) / 0.169 = 0.17 mol/L
Answer: 1.79 x 10^-5
Explanation: The equilibrium constant of a reaction can be calculated from the quotient of the concentrations of the products over the concentrations of the reactants, with each termed raised to their respective stoichometric coefficients.
For acetic acid, this equilibrium expression is:
![Kc=\frac{[H+] [CH3COO-]}{[CH3COOH]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH%2B%5D%20%5BCH3COO-%5D%7D%7B%5BCH3COOH%5D%7D)
Replacing the equilibrium concentrations given by the exercise into the expression above, the equilibrium constant, Kc will be obtained and it is found to be equal to 1.79 x 10^-5.
Answer:
The pH at the equivalence point is lower than 7
Explanation:
Given the titration involves a strong acid and a weak base
An example is the reaction between ammonia and hydrochloric acid in the aqueous phase
The pH of the base will ordinarily start high and drop rapidly with the additions of acid. As the equivalence point is approached, the pH will change more gradually, until finally one drop will cause a rapid pH transition through the equivalence point.
If a chemical indicator is used—methyl orange would be a good choice in this case—it changes from its basic to its acidic colour.
In strong acid-weak base titrations, the pH at the equivalence point is not 7 but below it. This is due to the production of a conjugate acid during the titration; it will react with water to produce hydronium ions.