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Serjik [45]
3 years ago
11

What are two systems that use radio waves

Chemistry
1 answer:
Goshia [24]3 years ago
7 0
Mobile radio communication
Broadcasting
Navigation systems
You might be interested in
PLEASE ANSWER ASAP!!!!!!! 50 points if the answer is correct!
Ad libitum [116K]

5

 mL acetic acid

95

mL water

Explanation:

Since

5

%

of the vinegar, by volume, is acetic acid, and we have

100

mL of vinegar, we have

5

mL of vinegar.

Similarly, we have

100

%

−

5

%

=

95

%

being water, so we have

95

mL of water.

8 0
3 years ago
How would the freezing point of seawater compare with that of pure water?
Alisiya [41]
Pure water has a freezing point of 0 degrees centigrade but seawater has a lower freezing point because of the salt (NaCl) 
6 0
4 years ago
4. What is the total mass of ice that can be vaporized by 2100 kJ of heat energy?
anygoal [31]

Answer:

5 g

Explanation:

The heat required to vaporize ice is the sum of

i) Heat required to melt ice at 0°C

ii) Heat required to raise the temperature from  0°C to 100°C

iii) Heat required to vaporize water at 100°C

Thus;

H = nLfus + ncθ + nLvap

H= n(Lfus + cθ + Lvap)

Lfus = 6.01 kJ/mol

Lvap = 41 kJ/mol

c = 75.38

n =?

2100 = n(6.01  + 75.38(100) + 41)

n = 2100 KJ/7585.01 kJ/mol

n = 0.277 moles

Mass of water = number of moles * molar mass

Mass of water = 0.277 moles * 18 g/mol

Mass of water =  5 g

3 0
3 years ago
A 0.150-kg sample of a metal alloy is heated at 540 Celsius an then plunged into a 0.400-kg of water at 10.0 Celsius, which is c
Zarrin [17]

Answer:

C_{alloy}=0.497\frac{J}{g\°C}

Explanation:

Hello there!

In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:

Q_{allow}=-(Q_{water}+Q_{Al})

Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:

m_{alloy}C_{alloy}(T_{eq}-T_{alloy})=-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})

Then, we solve for specific heat of the metallic alloy to obtain:

C_{alloy}=\frac{-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})}{m_{alloy}(T_{eq}-T_{alloy})}

Thereby, we plug in the given data to obtain:

C_{alloy}=\frac{-(400g*4.184\frac{J}{g\°C} (30.5\°C-10.0\°C)+200g*0.900\frac{J}{g\°C}(30.5\°C-10.0\°C)}{150g(30.5\°C-540\°C)} \\\\C_{alloy}=0.497\frac{J}{g\°C}

Regards!

3 0
3 years ago
The addition of perchloric acid to pure water causes the conductivity to _________.
Olin [163]
Adding perchloric acid to water would cause it's conductivity to increase.
3 0
3 years ago
Read 2 more answers
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