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MariettaO [177]
3 years ago
15

Researchers at the University of Georgia have evaluated trends in streamside forests in areas within roughly 400 feet of the sta

te’s streams and rivers. A decline in streamed forests is evident across much of the state. Between 1974 and 2005, 41 of the state’s 52 large watersheds showed declines in riparian forests. The greatest losses were in the Upper Chattahoochee, Middle Savannah, Upper Ocmulgee, and Middle Chattahoochee.
Stream-side or riparian land lies directly along rivers, streams, and other bodies of water and provide benefit to the aquatic ecosystems in ALL BUT ONE of the ways listed here.
A) helps to maintain stream temperatures
B) adds aesthetic value to the landscape
C) riparian vegetation traps and removes pollutants
D) produces organic matter that aquatic animals use as food

Physics
1 answer:
Colt1911 [192]3 years ago
6 0
<span>B: adds aesthetic value to the landscape. Think about it, out of all your options, that's the one that doesn't really help anything.

And I took the test, so take my word for it.</span>
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A stone that starts at rest free falls for 7.0 s. How far does the stone fall in this time?
vredina [299]

Gravitational acceleration is approx 9.8 m/s
Time is 7s

a=9.8 m/s
t=7s

a = d/t^2

therefore:

d = a * t^2

d = 9.8 * 7^2

d = 9.8 * 49

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Does heating a cup of water allow it to dissolve more sugar? Temperature of the water is measured in degrees Centigrade. Amount
mixas84 [53]

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Two blocks of masses M 1 and M 2 are connected by a massless string that passes over a massless pulley as shown in the figure. M
stealth61 [152]

The mass M1 is 7.8 kg

Explanation:

Block M1 is hanging on the string while block M2 is on the frictionless ramp.

We have to write the equations of motion for the two blocks.

- For M1, the only two forces acting on it are the force of gravity M_1 g (downward) and the tension in the string T (upward). So we can write

M_1 g - T = M_1 a

where

M_1 is the mass of the block

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a is the acceleration of the system

- For M2, the only two forces acting on it are the tension in the string T (acting up along the ramp) and the component of the gravity acting down along the ramp, M_2 g sin \theta. So the equation of motion is

T-M_2 g sin \theta = M_2 a

where

M_2 = 13.5 kg is the mass of the 2nd block

\theta=35.5^{\circ} is the angle of the ramp

In order for the two blocks to be in equilibrium, the acceleration must be zero:

a=0

So the two equations become:

M_1 g - T=0\\T-M_2 g sin \theta = 0

Isolating T from the 1st equation,

T=M_1 g

And substituting into the 2nd equation, we can find the value of the mass M_1:

M_1 g - M_2 g sin \theta = 0\\M_1 = M_2 sin \theta = (13.5)(sin 35.5^{\circ})=7.8 kg

Learn more about acceleration and forces:

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What is the wavelenght and the frequencen of walkie-talkie?
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I hope this helps! :)
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