Researchers at the University of Georgia have evaluated trends in streamside forests in areas within roughly 400 feet of the sta
te’s streams and rivers. A decline in streamed forests is evident across much of the state. Between 1974 and 2005, 41 of the state’s 52 large watersheds showed declines in riparian forests. The greatest losses were in the Upper Chattahoochee, Middle Savannah, Upper Ocmulgee, and Middle Chattahoochee.
Stream-side or riparian land lies directly along rivers, streams, and other bodies of water and provide benefit to the aquatic ecosystems in ALL BUT ONE of the ways listed here.
A) helps to maintain stream temperatures
B) adds aesthetic value to the landscape
C) riparian vegetation traps and removes pollutants
D) produces organic matter that aquatic animals use as food
Stream-side or riparian land lies directly along rivers, streams, and other bodies of water and provide benefit to the aquatic ecosystems in ALL BUT ONE of the ways listed here.
A) helps to maintain stream temperatures
B) adds aesthetic value to the landscape
C) riparian vegetation traps and removes pollutants
D) produces organic matter that aquatic animals use as food
1 answer:
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To solve this problem, we must know the gravitational force of the planet. The equation would be,
This would calculate the force between two objects with masses m1 and m2 and the gravitational constant, G, is 6.67 x 10^-11 m3 s-2 kg-1 and with r as the distance between the objects.
Thus,
F = (6.67 x 10^-11 m3 s-2 kg-1) * (5.68 x 10^26 kg) * (65 kg) * ((1/6.03 x 10^7 m)^2)
F = 678 kg/s^2 or 678 N
Answer is letter B.
Answer:
a) 0 J
b) W = nRTln(Vf/Vi)
c) ΔQ = nRTln(Vf/Vi)
d) ΔQ = W
Explanation:
a) To find the change in the internal energy you use the 1st law of thermodynamics:
Q: heat transfer
W: work done by the gas
The gas is compressed isothermally, then, there is no change in the internal energy and you have
ΔU = 0 J
b) The work is done by the gas, not over the gas.
The work is given by the following formula:
n: moles
R: ideal gas constant
T: constant temperature
Vf: final volume
Vi: initial volume
Vf < Vi, then W < 0 and the work is done on the gas
c) The gas has been compressed. Thus, its temperature increases and heat has been transferred to the gas.
The amount of heat is equal to the work done W
d)
Answer:
Explanation:
Using the first law of thermodynamics:
Where is the change in the internal energy of the system, in this case
,
is the heat tranferred, and
is the work,
with a negative sign since the work is done by the system.
From the previous equation we solve for heat, because it is the unknown variable in this problem
And replacing the known values:
The negative sign shows us that the heat is tranferred from the system into the surroundings.