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Irina-Kira [14]
4 years ago
8

Which expression is equal to the number of grams in 2.43 kilograms

Chemistry
1 answer:
KiRa [710]4 years ago
3 0
1 kg = 1000g
2.43 kg *1000g/1kg = 2430 g
You might be interested in
A room is a cube that measures 4 meters in each dimension. If the temperature changes from 10 C to 30 C, and the pressure decrea
Katen [24]

Answer:

More air will enter the room since the volume of the room increases.

Explanation:

We'll begin by calculating the initial volume (V₁) of the room. This can be obtained as follow

Length (L) of room = 4 m

Initial volume (V₁) =..?

V₁ = L³

V₁ = 4³

V₁ = 64 m³

Next, we shall determine if there is an increase in the volume of the room or not. This can be obtained as follow:

Data obtained from the question include:

Initial volume (V₁) = 64 m³

Initial temperature (T₁) = 10 °C + 273 = 283 K

Final temperature (T₂) = 30 °C + 373 = 303 K

Initial pressure (P₁) = 760 mmHg

Final pressure (P₂) = 718 mmHg

Final volume (V₂) =?

P₁V₁/T₁ = P₂V₂/T₂

760 × 64 / 283 = 718 × V₂ / 303

48640 / 283 = 718 × V₂ / 303

Cross multiply

283 × 718 × V₂ = 48640 × 303

203194 × V₂ = 14737920

Divide both side by 203194

V₂ = 14737920 / 203194

V₂ = 72.53 m³

SUMMARY

Initial volume (V₁) of room = 64 m³

Final volume (V₂) of room = 72.53 m³

From the calculations made above, we can see that the volume of the room increases from 64 m³ to 72.53 m³. Thus more air will enter the room since the volume of the room increases.

6 0
3 years ago
The argon atoms are excited into an excited state before emitting the 488.0 nm laser. It is known that the energy of the first i
Jobisdone [24]

Answer:

Explanation:

Given that:

The argon atoms are excited into an excited state before emitting the 488.0 nm laser.

the energy of the first ionization energy of argon is 1520 kJ mol-1.

SInce 1 eV = 96.49 kJ/mol

Therefore, the energy of the first ionization energy of argon in eV is = ( 1520/ 96.49) eV

=  15.75 eV

To find where  the energy level of the excited state lies below the vacuum energy level, let's first determine, the energy liberated by using planck expression.

E = \dfrac{hc}{\lambda}

E  = \dfrac{6.6 \times 10^{-34} \times 3 \times 10^8}{488 \times 10^{-9}}

E  = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}

E  = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}

E  =4.057 \times 10^{-19} \ J

Converting Joules (J) to eV ; we get,

E  =\dfrac{4.057 \times 10^{-19}}{1.6 \times 10^{-19}}

E = 2.53 eV

The energy levels of the first exited state = -13.223 eV

8 0
3 years ago
Ionic bond occurs between two atoms that have different:
Len [333]

Answer:

Ionic bond occurs between two atoms that have different:

a) Electron

Explanation:

according to the definition of ionic bond,

it is the electrostatic force of attraction that holds the two oppositely charged ions together and an ionic bond or electrovalent bond is formed when one atom gains electrons while the other atom loses electrons from its outermost level or orbit.

7 0
3 years ago
Which of these is the best definition for disintegration? A. when rock becomes moist B. when rock is physically broken into smal
lions [1.4K]
<span>B. when rock is physically broken into smaller pieces</span>
5 0
3 years ago
4. Write the chemical formula for each of the following:
NikAS [45]

Answer:

Calcium oxide: CaO

Copper (II) nitrate: Cu(NO₃)₂

Ammonium chloride: NH₄Cl

Magnesium sulfate: MgSO₄

Copper (I) oxide: Cu₂O

Calcium chloride: CaCl₂

Explanation:

Hello there!

In this case, according the IUPAC rules for naming this inorganic salts, whereas calcium, copper (II), ammonium, magnesium and copper (I) are the cations and oxide, nitrate, chloride and sulfate are the anions, we proceed as follows:

Calcium oxide: CaO

Copper (II) nitrate: Cu(NO₃)₂

Ammonium chloride: NH₄Cl

Magnesium sulfate: MgSO₄

Copper (I) oxide: Cu₂O

Calcium chloride: CaCl₂

Best regards!

6 0
3 years ago
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