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malfutka [58]
3 years ago
6

Benzaldehyde, C6H5CHO, has a normal boiling point of 179.0 ∘C and a critical point at 422 ∘C and 45.9 atm.

Chemistry
1 answer:
Naya [18.7K]3 years ago
5 0
Ln(P2/P1) = (L/R).(1/T1 - 1/T2) 

<span>with P1 = 1 atm, P2 = 45.9 atm, R = 8.314 J/mol.K, T1 = 452.15 K, T2 = 695.15 K. This gave the latent heat L as 41.2 kJ/mol.K. </span>

<span>Using this value, and calculating the vapour pressure at 120°C = 393.15 K </span>

<span>ln(P2) = (41.2 x 10^3/8.314).(1/452.15 - 1/393.15) </span>

<span>which gives the vapour pressure P2 as 0.1931 atm = 146.7 torr. </span>
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alexgriva [62]

Answer:

Bacterial species are typified by their diversity. There are three notable common traits of bacteria, 1) lack of membrane-bound organelles, 2) unicellular and 3) small (usually microscopic) size.

Explanation:

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4 0
3 years ago
In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
Determine how many moles are present in 0.23kg of SO(2)
Rama09 [41]

Answer:

3.59 moles

Explanation:

Hopefully this helps! :)

Mark as brainliest if right!

6 0
3 years ago
PLEASE PLEASE HELP ME!!!A 450 ml gas sample has a pressure of 1.25 atm at 65 °C. What is the temperature, in °C, at which the ga
Arlecino [84]

Answer:

89°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

(1.25 atm)(450 mL)/(65°C) = (0.89 atm)(865 mL)/T₂

8.653846154 = 769.85/T₂

T₂ = 769.85/8.653846154

T₂ = 88.96044444 = 89°C

6 0
3 years ago
The equation most often associated with Newton's Second Law of Motion is
nignag [31]

Answer:

F = ma or Force = mass x acceleration.

Explanation:

Newtons second law is about the force put onto an object. To find this you would use the formula:

Force is equal to mass times acceleration (F=ma)

7 0
3 years ago
Read 2 more answers
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