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malfutka [58]
3 years ago
6

Benzaldehyde, C6H5CHO, has a normal boiling point of 179.0 ∘C and a critical point at 422 ∘C and 45.9 atm.

Chemistry
1 answer:
Naya [18.7K]3 years ago
5 0
Ln(P2/P1) = (L/R).(1/T1 - 1/T2) 

<span>with P1 = 1 atm, P2 = 45.9 atm, R = 8.314 J/mol.K, T1 = 452.15 K, T2 = 695.15 K. This gave the latent heat L as 41.2 kJ/mol.K. </span>

<span>Using this value, and calculating the vapour pressure at 120°C = 393.15 K </span>

<span>ln(P2) = (41.2 x 10^3/8.314).(1/452.15 - 1/393.15) </span>

<span>which gives the vapour pressure P2 as 0.1931 atm = 146.7 torr. </span>
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alex41 [277]
<span>1. Balance the reaction
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag 
2. Find the limiting [divide moles of reactant by their balancing numbers]
Cu: 4.2/1 =4.2 
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How many moles of silver metal will be formed?
The ratio between the limiting reactant and silver is 2:2 or 1:1
therefore 6.3 moles of silver will be formed.

How many moles of excess reactant will be left?
Since each mole of copper is equal to 2 moles of AgNO3. divide 6.3 by 2 then minus it from coppers moles
6.3/2 = 3.15
4.2-3.15 = 1.05 moles of copper will be left
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