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valkas [14]
3 years ago
14

We can determine the ____________ of a wave when given the frequency and the wavelength.

Physics
1 answer:
kotykmax [81]3 years ago
6 0
<span>We can determine the "Velocity" of</span><span> a wave when given the frequency and the wavelength.

So, option B is your answer.

Hope this helps!
</span>
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A race-car drives around a circular track of radius RRR. The race-car speeds around its first lap at linear speed v_iv i ​ v, st
Bond [772]

Answer and Explanation: <u>Centripetal</u> <u>Acceleration</u> is the change in velocity caused by a circular motion. It is calculated as:

a_{c}=\frac{v^{2}}{r}

v is linear speed

r is radius of the curve the object in traveling along

For its first lap:

a_{c}_{1}=\frac{v_{i}^{2}}{R}

After a while:

a_{c}_{2}=\frac{(4v_{i})^{2}}{R}

a_{c}_{2}=\frac{16v_{i}^{2}}{R}

Comparing accelerations:

\frac{a_{c}_{2}}{a_{c}_{1}}=\frac{16.v_{i}^{2}}{R}.\frac{R}{v_{i}^{2}}

\frac{a_{c}_{2}}{a_{c}_{1}}=\frac{16.v_{i}^{2}}{R}.\frac{R}{v_{i}^{2}}

\frac{a_{c}_{2}}{a_{c}_{1}}=16

a_{c}_{2}=16a_{c}_{1}

<u>With linear speed </u><u>4 times faster</u><u>, centripetal acceleration is </u><u>16 times greater.</u>

4 0
3 years ago
16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radi
ArbitrLikvidat [17]

The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C

<h3>What does Orbital speed depend on ?</h3>

The speed of an object travelling around a circle depends on two quantities namely;

  • Its angular velocity w
  • Its distance from the center of the circle.

Given that  an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)

The given parameters are:

  • The mass of Saturn = 5.68 x 10^26 kg
  • The orbital radius = 3.00 x 105 km
  • G = 6.67 × 10-11 N·m2/kg2

Let us first calculate the gravitational field strength on the Saturn.

g = GM/r²

Substitute all the necessary parameters and convert km to m

g = (6.67 × 10^{-11} × 5.68 × 10^{26}) ÷ (300000 × 1000)²

g = 3.79 × 10^{16} ÷ 9 × 10^{16}

g = 0.421 m/s²

The  orbital speed will be

V² = gr

V² = 0.4211 × 300000 × 1000

V² = 126333333.3

V = √126333333.3

V = 11239.8 m/s

Convert it to Km/s by dividing the answer by 1000

V = 11239.8/1000

V = 11.2 Km/s

Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s

Learn more about Orbital Speed here: brainly.com/question/22247460

#SPJ1

4 0
1 year ago
Between two objects.
Ira Lisetskai [31]

Answer:

C Friction

Explanation:

6 0
3 years ago
Thiết bị nào sau đây không phải là nguồn điện
kumpel [21]

Thiết bị không phải nguồn điện:

Đáp án D

7 0
3 years ago
A car with an initial velocity of O m/s and a mass of 1500 kg reaches a velocity of 15 m/s in 5
Flura [38]

Answer:the answer can be find out by the following steps;

Explanation:

3 0
3 years ago
Read 2 more answers
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