2 years ago

Am 1 years old UwU (JK 15)

Physics

1 answer:

igomit [66]2 years ago

7 0

Answer:

so am i ._. 15 not 1 ofc lol

Explanation:

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a charge of 7.2x10^-5C is placed in an Electric field with a strength of 4.8x10^5N/C. if the Electric potential energy of the ch

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Answer:

$d= 2.2 m$

Explanation:

The data given in the question is

Charge : q = $7.2 \times 10^{-5} C$

Electric field Strength : E = $4.8 \times 10^{5} N/C$

Electrical potential Energy : U = $75J$

Let, the distance be "d"

So, the formula for Electrical potential energy is

$U= q \times E \times d$

Simplified formula for distance become

$d=\frac{U}{q \times E}$

Now , insert the value

$d=\frac{75 J}{7.2 \times 10^{-5}C \times 4.8 \times 10^5 N/C}$

or,

$d=2.17 m$

Rounding off

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3 years ago