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lakkis [162]
4 years ago
5

What fundimental force is responsible for the repulsion between two positively charged particles?

Physics
1 answer:
Aliun [14]4 years ago
4 0
Coulomb interaction is responsible
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*Urgent* I WILL GIVE BRAINLIEST
Butoxors [25]

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school​ both take up energy, unlike walking to school.

unless ur talking about energy, counting energy you produce and use to complete things, then it would be the 3rd one, taking the bus to school.

4 0
3 years ago
Frequency refers to the number of wavelengths that pass a fixed point in a minute. true or false
Art [367]
Frequency refers to the number of wavelengths that pass a fixed point in a minute. true or false

Answer:True
7 0
4 years ago
7. Find the speed of a 22 kg mass with a momentum of 450 kgm/s. (Round
jeyben [28]

Answer:

i don't know if this is right but here,9900 kgm/s

Explanation:

calculator UwU

6 0
4 years ago
What is the velocity of an electron that has a de Broglie wavelength approximately the length of a chemical bond? Assume this le
melomori [17]

Answer : The velocity of an electron is, 6.1\times 10^{6}m/s

Explanation :

According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{p}

and,

p=mv

where,  

p = momentum, m = mass, v = velocity

So, the formula will be:

\lambda=\frac{h}{mv}       .............(1)

where,

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength  = 1.2\times 10^{-10}m

m = mass  of electron = 9.11\times 10^{-31}kg

v = velocity of electron = ?

Now put all the given values in formula 1, we get:

1.2\times 10^{-10}m=\frac{6.626\times 10^{-34}Js}{(9.11\times 10^{-31}kg)\times v}

v=6.1\times 10^{6}m/s

Thus, the velocity of an electron is, 6.1\times 10^{6}m/s

6 0
4 years ago
If mr galans paces is equal to 1.8 m,how many paces would it take to get to the moon
Anettt [7]

Answer:

The number of paces it would take to get to the Moon is 213,555,556 paces

Explanation:

The given length of Mr Galan's paces = 1.8 m/pace

The distance from the Earth to the Moon is, 384,400 km = 384,400,000 m

Therefore, the number of paces, "n", it would take to get to the Moon from the Earth is given as follows;

n = (The distance from the Earth to the Moon)/(The length of each Mr Galan's paces)

∴ n = 384,400,000 m/(1.8 m/pace) = 213,555,556 paces

The number of paces it would take to get to the Moon = n = 213,555,556 paces

5 0
3 years ago
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