What is the numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall?
2 answers:
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Answer:
Displacement is 565.69 m at 45° west of north
Explanation:
Let north represent positive y axis and east represent positive x axis.
We have journey started from 600 N. Michigan Avenue, and walked 3 blocks toward north, 4 blocks toward west, and 1 block toward north to a train station.
3 blocks toward north = 300 j m
4 blocks toward west = -400 i m
1 blocks toward north = 100 j m
Total displacement = -400 i + 400 j m
Magnitude
Direction,
Direction is 45° west of north.
Displacement is 565.69 m at 45° west of north
Answer:
speed of a particle = 2.31 × m/s
energy of proton required = 27.77 KeV
energy of electron required = 15.171 eV
Explanation:
given data
magnetic field of magnitude = 0.22 T
electric field of magnitude = 0.51 MV/m
to find out
speed of a particle and energy must protons have to pass through undeflected and energy must electrons have to pass through undeflected
solution
we know that force due to magnetic and electric field is express as
force due to magnetic field B = qvB ..............1
and force due to electric field E = qE .....................2
so without deflection force due to magnetic field = force due to electric field
so here qvB = qE
and V = ...................3
put here value
V =
speed of a particle = 2.31 × m/s
and
now energy of proton required will be here as
energy of proton required = mass of proton ×
put here value
energy of proton required = 1.67 × ×
energy of proton required = 4.45 × J
energy of proton required = 4.45 × J ÷ (1.602 ×
energy of proton required = 27777.777 eV
energy of proton required = 27.77 KeV
and
now we get here energy of electron required that is
energy of electron required = mass of electron ×
put here value
energy of electron required = 9.11 × ×
energy of electron required = 24.305× J
energy of electron required = 24.305 × J ÷ (1.602 ×
energy of electron required = 15.171 eV