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3 years ago

What is the numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall?

Physics

2 answers:

Nuetrik [128]3 years ago

8 0

Answer:

9.8 m/s/s

Explanation:

The numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall is 9.8 m/s/s. This is called the acceleration due to gravity.

Savatey [412]3 years ago

6 0

Answer: 9.8

The velocity of a free-falling object can be discovered by using a simple mathematical formula: v = (9.8 m/s2) * time

Explanation:

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Read 2 more answers

A soccer ball is released from rest at the top of a grassy incline. After 6.2 seconds, the ball travels 47 meters. One second la

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Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

Explanation:

(a)

We will use the second equation of motion here:

$s = v_it+\frac{1}{2}at^2$

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

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Therefore,

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(b)

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$s = v_it+\frac{1}{2}at^2$

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

$s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\$

s = 63.24 m

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