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SSSSS [86.1K]
3 years ago
6

A curved line going up indicates the object is

Physics
1 answer:
Vesna [10]3 years ago
8 0

Explanation:

Both graphs show plotted points forming a curved line. Curved lines have changing slope; they may start with a very small slope and begin curving sharply (either upwards or downwards) towards a large slope. In either case, the curved line of changing slope is a sign of accelerated motion (i.e., changing velocity).

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What two scientists played a big role in studying the origins of the universe?
jeka94
Edwin Hubble and Albert Einstein.
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3 years ago
you are assigned to do some calculations for a movie stunt that involves a car on a straight road. the road pictured above has a
Vlada [557]

Calculate the time it takes for the car to reach the beginning of the hill given that acceleration as already found in part a is 2.89 m/s²

Answer:

5.88 s

Explanation:

Using kinematic equation, v=u+at where v and u are the final and initial velocities respectively, a is acceleration and t is time.

Considering the first part, acceleration is already found as 2.89 m/s and the final velocity is given as 17 m/s while the initial velocity is zero since it is at rest.

Making t the subject of formula then

t=(v-u)/a

Substituting the given figures then

t=(17-0)/2.89=5.8823529411764s

Rounded off, t=5.88 s

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3 years ago
In flight, a rocket is subjected to four forces; weight, thrust, lift, and drag. Forces are vector quantities that have both a m
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Answer:

thrust

Explanation:

4 0
3 years ago
Read 2 more answers
A particle's velocity is described by the function vx = kt 2 m/s, where k is a constant and t is in s. The particle's position a
vodomira [7]

Answer:

The value of the constant k is 2

Explanation:

We have the equation of the velocity v_{x} = kt² , where k

is constant and t is the time in second

The particle's position at t_{0} = 0 is x_{0} = -9 m

The particle's position at t_{1} = 3 s is x_{1} = 9 m

We need to find the value of the constant k

The relation between the velocity and the displacement in a particular

time is x = \int\ {v_{x} } \, dt

Remember in integration we add power by 1 and divide the expression

by the new power

→ x = \int\ {kt^{2} } \, dt=\frac{1}{3}kt^{3}+c

c is the constant of integration to find it substitute the initial value of x

and t in the equation of x

→ t_{0} = 0 , x_{0} = -9 m

→ -9 = \frac{1}{3} k (0)³ + c

→ -9 = c

Substitute the value of c in the equation of x

→ x = \frac{1}{3} k t³ - 9

To find k substitute the values of  t_{1} = 3 s , x_{1} = 9 m

→ 9 = \frac{1}{3} k (3)³ - 9

→ 9 = \frac{1}{3} (27) k - 9

→ 9 = 9 k - 9

Add 9 to both sides

→ 18 = 9 k

Divide both sides by 9

→ k = 2

<em>The value of the constant k is 2</em>

5 0
3 years ago
1.Which of the following is the best example of motion?A.Waving your armsB.Tossing and turning in your bedC.Walking from home to
vlabodo [156]

Answer:

A

Explanation:

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3 years ago
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