Edwin Hubble and Albert Einstein.
Calculate the time it takes for the car to reach the beginning of the hill given that acceleration as already found in part a is 2.89 m/s²
Answer:
5.88 s
Explanation:
Using kinematic equation, v=u+at where v and u are the final and initial velocities respectively, a is acceleration and t is time.
Considering the first part, acceleration is already found as 2.89 m/s and the final velocity is given as 17 m/s while the initial velocity is zero since it is at rest.
Making t the subject of formula then
t=(v-u)/a
Substituting the given figures then
t=(17-0)/2.89=5.8823529411764s
Rounded off, t=5.88 s
Answer:
The value of the constant k is 2
Explanation:
We have the equation of the velocity
= kt² , where k
is constant and t is the time in second
The particle's position at
= 0 is
= -9 m
The particle's position at
= 3 s is
= 9 m
We need to find the value of the constant k
The relation between the velocity and the displacement in a particular
time is x = 
Remember in integration we add power by 1 and divide the expression
by the new power
→ x = 
c is the constant of integration to find it substitute the initial value of x
and t in the equation of x
→
= 0 ,
= -9 m
→ -9 =
k (0)³ + c
→ -9 = c
Substitute the value of c in the equation of x
→ x =
k t³ - 9
To find k substitute the values of
= 3 s ,
= 9 m
→ 9 =
k (3)³ - 9
→ 9 =
(27) k - 9
→ 9 = 9 k - 9
Add 9 to both sides
→ 18 = 9 k
Divide both sides by 9
→ k = 2
<em>The value of the constant k is 2</em>