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andrew-mc [135]
3 years ago
11

-2 3/4 on a number line how would I do that

Mathematics
1 answer:
lesya [120]3 years ago
5 0
This is an example I put a dot where -2 3/4 should be

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Please help!!! Will give brainliest
AlladinOne [14]

Answer:

option C

Step-by-step explanation:

option C is the correct answer of this question.

<em>plz </em><em>mark</em><em> my</em><em> answer</em><em> as</em><em> brainlist</em><em> plzzzz</em><em> vote</em><em> me</em><em>.</em>

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5 0
2 years ago
A lighthouse keeper has a 10 degrees angle of depression between the horizontal light beam and the line of sight from the ship.
Andrei [34K]
107.75m
This is a trigonometric ratio problem. the angle of depression (10) is opposite the height (19m) and the distance is adjacent to the distance (x). opposite ad adjacent sides to the angle is a tangent problem.
tan \theta = \frac{opp}{adj}
plus in values, we know.
tan (10) = \frac{19}{x}
switch tan(10) and x using the products property.
x = \frac{19}{tan (10)}
plug in to calulator to get answer
x=107.75

4 0
3 years ago
Which equation could be used to find the height of the flagpole
Sauron [17]
X = height of pole (in meters)

With respect to the 50 degree angle, the side x is the opposite leg. It is the leg furthest from the reference angle. The hypotenuse is 5 meters. 

The trig function sine ties together the opposite and hypotenuse

sin(angle) = opposite/hypotenuse
sin(50) = x/5
5*sin(50) = x .... multiply both sides by 5
x = 5*sin(50)

------------------

Since x = 5*sin(50) isn't listed as an answer choice, let's try using cosine. We can't use it right away because we don't know the adjacent side. What we can do is change the reference angle. The missing angle of the triangle is 90-50 = 40 degrees. Let's make the 40 degree angle the reference angle

So x is now the adjacent side with respect to the 40 degree reference angle. The hypotenuse is always the longest side. The hypotenuse stays at 5.

cos(angle) = adjacent/hypotenuse
cos(40) = x/5
5*cos(40) = x
x = 5*cos(40)

This expression is listed. The answer is choice B

4 0
3 years ago
T he equation for a parabola with directrix y = –p and focus (0, p) is:
zhuklara [117]

The equation for a parabola with directrix y = –p and focus (0, p)

The distance between vertex and directrix is P

Also the distance between vertex and focus is also P

Focus (0,p) so focus lies on y axis

Directrix line is paralled to focus point

So Directex crosses the x axis .

Hence line of symmetry lies is the y-axis.

The graph is attached below.


3 0
3 years ago
Find the absolute maximum and absolute minimum for f (x )equals x cubed minus 2 x squared minus 4 x plus 2 on the interval 0 les
sineoko [7]

9514 1404 393

Answer:

  • maximum: 2
  • minimum: -6

Step-by-step explanation:

The extrema will be at the ends of the interval or at a critical point within the interval.

The derivative of the function is ...

  f'(x) = 3x² -4x -4 = (x -2)(3x +2)

It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...

  f(0) = 2

  f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6

  f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1

The absolute maximum on the interval is f(0) = 2.

The absolute minimum on the interval is f(2) = -6.

8 0
2 years ago
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