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antiseptic1488 [7]
3 years ago
6

A right triangle has a hypotenuse of 37 and a leg of 10. What is the second leg of the triangle?

Physics
1 answer:
Yuliya22 [10]3 years ago
7 0

Answer:

The second leg of the triangle is 35.62

Explanation:

Given that

Hypotenuse = 37

A leg = 10

Based on the above information

The second leg of the triangle is

According to the Pythagorean theorem

a^2 + b^2 = c^2

where,

a and b = legs

And, the c = hypotenuse.

Now put these values to the above formula

So,

10^2 + b^2 = 37^2

b^2 = 37^2 - 10^2

b^2 = 1269

b = sqrt(1269)

b = 35 .62

Hence, the second leg of the triangle is 35.62

The other leg is 35 mm.

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A 1.80-m string of weight 0.0126 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Neglect the v
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Answer:

W = 0.135 N

Explanation:

Given:

- y (x, t) = 8.50*cos(172*x -2730*t)

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Solution:

The general form of standing mechanical waves is given by:

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Where k = stiffness and w = angular frequency

Hence,

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- Tension in the string T:

                            T = Y*V^2

where Y: is the mass per unit length of the string.

- The tension T and weight attached W are equal:

                           T = W = Y*V^2 = (w/L*g)*V^2

                            W = (0.0126 / 1.8*9.81)*(13.78)^2

                            W = 0.135 N

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Explanation:

Mass of the wheel, m = 49 kg

Radius of the hoop, r = 0.73 m

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Final angular speed of the wheel, \omega_f=0

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I=mr^2

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I=26.11\ kg-m^2

We know that the work done is equal to change in kinetic energy.

W=\Delta E

W=\dfrac{1}{2}I(\omega_f^2-\omega_i^2)

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