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Answer:
1461.7 g of AgI
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI
Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:
Mole of AgI = 6.22 moles
Molar mass of AgI = 108 + 127
= 235 g/mol
Mass of AgI =?
Mass = mole × molar mass
Mass of AgI = 6.22 × 235
Mass of AgI = 1461.7 g
Therefore, 1461.7 g of AgI were obtained from the reaction.
Answer:
the solubility of the ionic solid decreases
Explanation:
If a salt MX is added to an aqueous solution containing the solute AX, the X^- ion is common to both of the salts. The presence of X^- in the solution will suppress the dissolution of AX compared to the solubility of AX in pure water. This observation is known as common ion effect in chemistry.
The origin of common ion effect is based on Le Chatelier's principle. The addition of a solute will drive the equilibrium position towards the left hand side.
It’s an element because oxygen is already a gas.
