Answer
a
Explanation:
the giraffe doesn't need carbon dioxide
The solids are characterized as amorphous and crystalline solids based on the arrangement of atoms. The solids that are amorphous are rubber, plastic, candle wax, and glass.
<h3>What are amorphous solids?</h3>
The solids have the arrangement of atoms in the lattice. The solids with an appropriate arrangement of atoms are crystalline solids. For example, sugar, graphite.
The solids with irregular arrangements of atoms in the lattice are amorphous solids. For example, glass, rubber.
Thus, the solids that are amorphous in nature are rubber, plastic, candle wax, and glass.
Learn more about amorphous solids, here:
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Answer:

Explanation:
Hello,
In this case, for the given information, we can compute the rate of disappearance of NO₂ by using the following rate relationship:

Whereas it is multiplied by the the inverse of the stoichiometric coefficient of NO₂ in the reaction that is 2. Moreover, the subscript <em>f</em> is referred to the final condition and the subscript <em>0</em> to the initial condition, thus, we obtain:

Clearly, it turns out negative since the concentration is diminishing due to its consumption.
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Answer : Both solutions contain
molecules.
Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain
molecules.
Avogadro's Number is
=
which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.
Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.
Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.
Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.
We can calculate the number of molecules for each;
Number of molecules =
;
∴ Number of molecules =
which will be = 
Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.