The original prize is $82 and the sale prize is 65.60 what is the % discount

Enter the first four terms of the sequence.

krek1111 [17]

Cmcnxncnxbznxnbcvxnxnxmxncbc

3 0

3 years ago

A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th

Gennadij [26K]

<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

$h(t) = -16t^2 + 84t + 20$

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

$\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m$

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

8 0

3 years ago

During second period, Kiera completed a grammar worksheet. Of the 90 questions, she got 70% right. How many questions did Kiera

ANEK [815]

Answer:

we conclude that Kiera got the right 63 questions.

Step-by-step explanation:

Total questions = 90

The percentage of correct question = 70%

Using the formula

The number of correct questions = 70% of 90

= [70/100] × 90

= 0.7 × 90

= 63

Therefore, we conclude that Kiera got the right 63 questions.

7 0

3 years ago

1

ankoles [38]

We subtract the 17 from the 981 to make the two sides even so it’s easier to calculate, 981 - 17 = 964, then divide that by 2, 964/2 = 482. So your answer is 482.

Would appreciate brainliest!

6 0

2 years ago

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

4 0

2 years ago