Answer:
BD = 35
Step-by-step explanation:
Calculate CD in right triangle ABC, then BD in right triangle BCD
Using Pythagoras' identity in both triangles.
The square on the hypotenuse is equal to the sum of the squares on the other two sides.
In Δ ADC
CD² + AD² = AC² , substitute values
CD² + 9² = 15²
CD² + 81 = 225 ( subtract 81 from both sides )
CD = 144 ( take the square root of both sides )
CD =
= 12
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In Δ BCD
BD² + CD² = BC² , substitute values
BD² + 12² = 37²
BD² + 144 = 1369 ( subtract 144 from both sides )
BD² = 1225 ( take the square root of both sides )
BD =
= 35
Problem: 2/7 (4+c)=6
1. 7/2 x 2/7 x (4+c)=7/2 x 6
2. 4+c=7 x 3
3. 4+c=21
4. c=21-4
Answer: c=17
Ok so the first thing you would do is input the number where The variables are in the equation so 8^2-5(4)/4
ANSWER
EXPLANATION
We want to add the two numbers:
0.82 + 0.35
Using the long addition method, we have:
0 . 8 2
+ 0 . 3 5
Start on the right hand side: