Empirical formula is the simplest ratio of whole numbers of components making up a compound.
empirical formula can be calculated as follows
C H O
mass 12.0 g 2.00 g 5.33 g
number of moles
12.0 g / 12 g/mol 2.00 g / 1 g/mol 5.33 g / 16 g/mol
= 1.00 mol = 2.00 mol = 0.333 mol
divide by the least number of moles
1.00 / 0.333 2.00 / 0.333 0.333/ 0.333
= 3.00 = 6.01 = 1.00
the number of atoms
C - 3
H - 6
O - 1
empirical formula is C₃H₆O
Answer:
[He]: 2s² 2p⁵.
[Ne]: 3s².
[Ar]: 4s² 3d¹⁰ 4p².
[Kr]: 5s² 4d¹⁰ 5p⁵.
[Xe]: 6s² 4f¹⁴ 5d¹⁰ 6p².
Explanation:
- Noble elements are used as blocks in writing the electronic configuration of other elements as they are stable elements.
He contains 2 electrons fill 1s (1s²).
So, [He] can be written before the electronic configuration of 2s² 2p⁵.
Ne contains 10 electrons fill (1s² 2s² 2p⁶).
So, [Ne] can be written before the electronic configuration of 3s².
Ar contains 18 electrons is configured as ([Ne] 3s² 3p⁶).
So, [Ar] can be written before the electronic configuration of 4s² 3d¹⁰ 4p².
Kr contains 36 electrons is configured as ([Ar] 4s² 3d¹⁰ 4p⁶).
So, [Kr] can be written before the electronic configuration of 5s² 4d¹⁰ 5p⁵.
Xe contains 54 electrons is configured as ([Kr] 5s² 4d¹⁰ 5p⁶).
So, [Xe] can be written before the electronic configuration of 6s² 4f¹⁴ 5d¹⁰ 6p².
Answer:
I'd say the answer is 19,900
Answer:
1.01 atm
Step-by-step explanation:
To solve this problem, we can use the <em>Combined Gas Laws</em>:
p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₂
p₁V₁T₂ = p₂V₂ Divide each side by V₂
p₂ = p₁ × V₁/V₂ × T₂/T₁
Data:
p₁ = 1.05 atm; V₁ = 285 mL; T₁ = 15.8 °C
p₂ = ?; V₂ = 292 mL; T₂ = 11.2 °C
Calculations:
(a) Convert <em>temperatures to kelvins
</em>
T₁ = (15.8+273.15) K = 288.95 K
T₂ = (11.2+273.15) K = 284.35 K
(b) Calculate the <em>pressure
</em>
p₂ = 1.05 atm× (285/292) × (284.35/288.95)
= 1.05 atm × 0.9760 × 0.9840
= 1.01 atm
