Command module ✅
service module
lunar module
annum module
Answer:
a) Maximum height reached above ground = 2.8 m
b) When he reaches maximum height he is 2 m far from end of the ramp.
Explanation:
a) We have equation of motion v²=u²+2as
Considering vertical motion of skateboarder.
When he reaches maximum height,
u = 6.6sin58 = 5.6 m/s
a = -9.81 m/s²
v = 0 m/s
Substituting
0²=5.6² + 2 x -9.81 x s
s = 1.60 m
Height above ground = 1.2 + 1.6 = 2.8 m
b) We have equation of motion v= u+at
Considering vertical motion of skateboarder.
When he reaches maximum height,
u = 6.6sin58 = 5.6 m/s
a = -9.81 m/s²
v = 0 m/s
Substituting
0= 5.6 - 9.81 x t
t = 0.57s
Now considering horizontal motion of skateboarder.
We have equation of motion s =ut + 0.5 at²
u = 6.6cos58 = 3.50 m/s
a = 0 m/s²
t = 0.57
Substituting
s =3.5 x 0.57 + 0.5 x 0 x 0.57²
s = 2 m
When he reaches maximum height he is 2 m far from end of the ramp.
Deforestation because it gets rid of the nature and soon the land will be empty and dry
Answer:
Explanation:
Using the formula : E = mc²
Where m = mass = 6.8 × 10^-6 kg
c = speed of light = 3 ×10^8 m/s
The amount of joules of energy that would be produced equals :
Plugging in our values :
E = mc²
E = (6.8 × 10^-6) kg × (3 ×10^8)²m/s
E = (6.8 × 10^-6) kg × 9 × 10^16 m/s
E = 61.2 × 10^(-6 + 16)
E = 61.2 × 10^10 J
