We can solve the problem by using the first law of thermodynamics:
![\Delta U= Q-W](https://tex.z-dn.net/?f=%20%5CDelta%20U%3D%20Q-W%20)
where
is the variation of internal energy of the system
Q is the heat added to the system
W is the work done by the system
In this problem, the variation of internal energy of the system is
![\Delta U=U_f-U_i=134 J-87 J=47 J](https://tex.z-dn.net/?f=%20%5CDelta%20U%3DU_f-U_i%3D134%20J-87%20J%3D47%20J%20)
While the heat added to the system is
![Q=500 J](https://tex.z-dn.net/?f=%20Q%3D500%20J%20)
therefore, the work done by the system is
![W=Q-\Delta U=500 J-47 J=453 J](https://tex.z-dn.net/?f=%20W%3DQ-%5CDelta%20U%3D500%20J-47%20J%3D453%20J%20)
Answer:
As given that the car maintains a constant speed v as it traverses the hill and valley where both the valley and hill have a radius of curvature R.
(i) At point C, the normal force acting on the car is largest because the centripetal force is up. gravity is down and normal force is up. net force is up so magnitude of normal force must be greater than the car's weight.
(ii) At point A, the normal force acting on the car is smallest because the centripetal force is down. gravity is down and normal force is up. net force is up so magnitude of normal force must be less than car's weight.
(iii) At point C, the driver will feel heaviest because the driver's apparent weight is the normal force on her body.
(iv) At point A, the driver will feel the lightest.
(v)The car can go that much fast without losing contact with the road at A can be determined as follow:
Fn=0 - lose contact with road
Fg= mv²/r
mg=mv²/r
v=sqrt (gr)
Answer:
Explanation:
Explanation: total displacement =3√2m. and total distance covered=14m. I hope this is right and helps u.
Mass of 1 staple = 6.8 g/210 staples
mass of 1 staple = 0.032380952 g
Hope that helps!!