Answer:
Al2O3 + 6HCl --> 2AlCl3 + 3H2O
Explanation:
Al: 2
O: 3
H: 6
Cl: 6
Balanced on both sides.
Answer:
(B) 0.038 M
Explanation:
Kc = [H2][I2]/[HI]^2
Let the equilibrium concentration of H2 be y M
From the equation of reaction, mole ratio of H2 to I2 formed is 1:1, therefore equilibrium concentration of I2 is also y M
Also, from the equation of reaction, mole ratio of HI consumed to H2 formed is 2:1, therefore equilibrium concentration of HI is (1 - 2y) M
1.6×10^-3 = y×y/(1 - 2y)^2
y^2/1-4y+4y^2 = 0.0016
y^2 = 0.0016(1-4y+4y^2)
y^2 = 0.0016 - 0.0064y + 0.0064y^2
y^2-0.0064y^2+0.0064y-0.0016 = 0
0.9936y^2 + 0.0064y - 0.0016 = 0
The value of y must be positive and is obtained by using the quadratic formula
y = [-0.0064 + sqrt(0.0064^2 - 4×0.9936×-0.0016)] ÷ 2(0.9936) = 0.0736 ÷ 1.9872 = 0.038 M
Answer:
1,171 fluid ounces of herbicide is sufficient for 2050 square meter.
Explanation:
If 300 square feet of land is sprayed by the herbicide at the rate of 16 liquid ounce, So 1,171 fluid ounces of herbicide is enough to cover the area of 2050 square meters.
Calculation:
First convert 300 square feet into meter which is equal to 28 square meter.
16 ounces of herbicide = 28 square meter
x ounces of herbicide = 1050 square meter
by cross multiplication we get
28 x = 16 x 1050
x = 32800/ 28
x = 1171 ounces of herbicide.
K⁺ has positive charge, the easiest way to form a bond is to connect to negatively charged ion. We have only one negative ion Cl⁻.
So, the answer is
C. Cl⁻.