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djverab [1.8K]
2 years ago
9

A piece of gold ingot with a mass of 301 g has a volume of 15.6 cm3 . calculate the density of gold.

Chemistry
1 answer:
Fantom [35]2 years ago
6 0

Answer:

            19.29 g.cm⁻³

Solution:

Data Given:

                             Mass  =  301 g

                             Volume  =  15.6 cm³

Formula Used:

                             Density  =  Mass ÷ Volume

Putting values,

                             Density  =  301 g ÷ 15.6 cm³

                            Density  =  19.29 g.cm⁻³

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Explanation:

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7 0
3 years ago
4 Al + 3 O2 --&gt; 2 Al2O3
SIZIF [17.4K]

Answer:

The answer to your question is 7.4 moles of Aluminum

Explanation:

Data

moles of Al = ?

moles of Al₂O₃ = 3.7

Balanced chemical reaction

                4 Al  +  3 O₂  ⇒  2 Al₂O₃

To solve this problem use proportions and cross multiplication. Use the coefficients of the balanced chemical equation.

                4 moles of Aluminum ----------------- 2 moles of Al₂O₃

                 x                                  ----------------- 3.7 moles of Al₂O₃

                            x = (3.7 x 4) / 2

                            x = 14.8 / 2

                            x = 7.4 moles of Aluminum

5 0
3 years ago
Twenty-four grams of magnesium metal reacts with sixteen grams of oxygen gas to form magnesium oxide. According to the law of co
DedPeter [7]
The law of conservation of mass dictates that the total mass of reactants must be equal to the total mass of the products. Thus:
mass(MgO) = mass(Mg) + mass(O)
mass(MgO) = 24 + 16
mass(MgO) = 40 g

The third option is correct.
4 0
3 years ago
Read 2 more answers
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