I'd say A: tidal waves. B, C, and D don't really seem to fit for me.
Step 1: Copy of one side of DNA strand is made (called mRNA, messenger RNA)
step 2: mRNA moves to cytoplasm, then ribosome
step 3: mRNA goes through ribosome 3 bases at a time
step 4: transfer RNA (tRNA) matches up with the open DNA bases
step 5: tRNA releases the amino acid at the top, which joins the chain of amino acids being produced
Let’s assume a wire-hair terrier is a true breed for wire hair with alleles (BB) and a smooth-hair terrier is true breed for smooth hair (bb). Allele B is dominant over its allele b. When these two terrier mated and produce offspring wire-hair terrier and smooth-hair terrier in the ratio 3:1.
Based on this result it can be inferred that –
a. The pattern of inheritance is monohybrid cross.
b.Genotype of wire-hair terrier (1BB and 2 Bb) and genotype of smooth-hair terrier is (bb)
c. Phenotype ratio will be 3:1 and genotypic ratio will be 1:2:1.
The bone is ulna. The ulna is a long bone found in the forearm that stretches from the elbow to the smallest finger, and when in anatomical position, is found on the medial side of the forearm. It runs parallel to the radius, the other long bone in the forearm, and is the larger and longer of the two. The radius or radial bone is one of the two large bones of the forearm, the other being the ulna. It extends from the lateral side of the elbow to the thumb side of the wrist and runs parallel to the ulna. The radius is shorter and smaller than the ulna.
