Answer:
The radius of a chamber is 2.36 meters.
Explanation:
Given that,
The outer wall moves at a speed of 2.72 m/s.
Mass of the person, m = 75.1 kg
The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :

r is the radius of a chamber


r = 2.36 meters
So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.
Answer:
a) Tc = 750 [N] ;b) See the explanation below.
Explanation:
To solve this problem, we first need a graphical explanation of this, as well as knowing the corresponding questions. Therefore, a search was carried out in google, in the attached image we will find a graphical description of the problem.
b)
The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.
a)
In this way we can find by means of a sum of forces on the y axis equal to zero:
- 850 - 450 + 550 + Tc = 0
Tc = 750 [N]
The answer is B.) I took the test.
Answer:
Just consider the resistance as water flowing through a pipe. If the pipe is too small in radius (consider thin wire as small pipe) water can’t flow easly. If the pipe is big in radius (consider thick wire as big pipe) water can flow easly. So flowing water through a small pipe for a long distance will inversly affect the normal flow where as flowing water through a big pipe for a small distance will not affect too much the normal flow.
So long & thin wire has high resistance. Short & thick wire has low resistance.
B. A wire that is 2 m long and has a cross-sectional area of 0.066
Answer:
Fx = 4.92 [N]
Fy = 0.868 [N]
Explanation:
Let's take the 10 degrees as a measure from the horizontal component to the vector.
Thus taking the components in the X & y axes respectively:
Fx = 5*cos(10) = 4.92 [N]
Fy = 5*sin(10) = 0.868 [N]