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Katena32 [7]
3 years ago
9

A roller coaster starts from rest at point a and continues to point b on a frictionless track. what best describes the changes i

n kinetic and potential energy as the car travels from point a to point b?
Physics
2 answers:
IceJOKER [234]3 years ago
5 0

Took a wild guess and got it correct. The answer is B Kinetic Energy increases and potential energy decreases.

saw5 [17]3 years ago
3 0

<span>At first when the car is at the datum point where is no elevation, the kinetic energy increases while the potential energy is zero. As it travel the path and goes upward the kinetic enrgy decreases while the potential energy increases. When it goes down again the kinetic enrgy increases again while the potential energy decreases </span>

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Use the drop-down menus to complete the statements. When the 5.0 kg cylinder fell 100 m, the final temperature of the water was
OLEGan [10]

Answer:

A. 26.17 B. 1.17 C. 30.86 D. 5.86

Explanation:

7 0
3 years ago
A spacecraft is fueled using hydrazine (N2H4; molecular weight of 32 grams per mole [g/mol]) and carries 1640 kilograms [kg] of
Sauron [17]

Answer:

The value is t = 689.029 \  hours

Explanation:

From the question we are told that

The molar mass of hydrazine is Z =  32 g/mol = \frac{32}{1000} = 0.032 \  kg/mol

The initial temperature is T_i  =  -186 ^o F = (-186-32) *\frac{5}{9} +273.15 = 152\ K

The final temperature is T_f  =  78 ^o F = (78-32) *\frac{5}{9} +273.15 = 298.7 \ K

The specific heat capacity is c_h  =  0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)

The power available is P = 300 \ W

The mass of the fuel is m =   1640 \  kg

Generally the number of moles of hydrazine present is

n  =  \frac{m}{Z}

=> n  =  \frac{1640}{= 0.032}

=> n  =  51250 \ mol

Generally the quantity of heat energy needed is mathematically represented as

Q =  n * c_h * (T_f -T_i)

=> Q =  51250  * 0.099 *10^3  * (298.7 - 152)

=> Q =  7.441516913 * 10^{8} \  J

Generally the time taken is mathematically represented as

t =  \frac{Q}{P}

=> t =  \frac{7.441516913 * 10^{8} }{300}

=> t = 2480505.6377 s

Converting to hours

t = \frac{2480505.6377}{3600}

=> t = 689.029 \  hours

6 0
3 years ago
A disk-shaped merry-go-round of radius 2.13 m and mass 175 kg rotates freely with an angular speed of 0.651 rev/s. A 55.4 kg per
GREYUIT [131]

Answer:

Explanation:

To find out the angular velocity of merry-go-round after person jumps on it , we shall apply law of conservation of ANGULAR momentum

I₁ ω₁ + I₂ ω₂ = ( I₁  + I₂ ) ω

I₁ is moment of inertia of disk , I₂ moment of inertia of running person , I is the moment of inertia of disk -man system , ω₁ and ω₂ are angular velocity of disc and man .

I₁ = 1/2 mr²

= .5 x 175 x 2.13²

= 396.97 kgm²

I₂ = m r²

= 55.4 x 2.13²

= 251.34 mgm²

ω₁ = .651 rev /s

= .651 x 2π rad /s

ω₂ = tangential velocity of man / radius of disc

= 3.51 / 2.13

= 1.65 rad/s

I₁ ω₁ + I₂ ω₂ = ( I₁  + I₂ ) ω

396.97 x  .651 x 2π + 251.34 x 1.65 = ( 396.97 + 251.34 ) ω

ω = 3.14 rad /s

kinetic energy = 1/2 I ω²

= 3196 J

8 0
3 years ago
Which is greater, the gravitational force between earth and the moon, or the force between earth and the sun?
Karo-lina-s [1.5K]
Earth and the Sun
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8 0
3 years ago
URGENT HELP PLEASE, GIVING BRAINLIEST IF YOU ANSWER CORRECTLY!! (20 pts!!)
Kobotan [32]
The answer is c 1386j

This calculator is very helpful I use it on my homework

https://www.omnicalculator.com/physics/specific-heat
8 0
2 years ago
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