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3 years ago

Physics pls help

Physics

2 answers:

seropon [69]3 years ago

3 0

First one is correct

WARRIOR [948]3 years ago

3 0

Answer: -0.33m/s (A)

Explanation:

According to the law of conservation of momentum, the sum of momentum before collision is equal to sum of their momentum after collision. They move with the same velocity (v) after collision.

Momentum = mass × velocity

For 4kg mass with velocity of 3m/s,

Its momentum = 4×3 = 12kgm/s

For 8kg mass with velocity of 2m/s,

Its momentum = 8 × -2 = -16kgm/s.

The velocity of 8kg mass is negative because it is moving towards the left(-ve x-direction).

Sum of momentum before collision = 12+(-16) = -4kgm/s... (1)

Momentum of 4kg body after collision = 4v

Momentum of 8kg body after collision = 8v

Sum of momentum after collision = 4v+8v = 12v...(2)

Equating 1 and 2 according to law of conservation of momentum, we have;

-4 = 12v

V = -4/12

V = -0.33m/s

Therefore their velocity after collision is -0.33m/s

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3 years ago

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3 years ago

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Veseljchak [2.6K]

Answer:

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3 years ago

A pitcher throws a 0.140 kg baseball, and it approaches the bat at a speed of 35.0 m/s. The bat does Wnc = 75.0 J of work on the

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Answer:

The speed of the ball is 42.5 m/s

Explanation:

The initial kinetic energy of the ball is:

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The speed of the ball after leaving the bat is:

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