Answer:
v = 5.88 10⁷ m / s
Explanation:
For this exercise we use the relation
E = m c²
also indicate that all energy is converted into kinetic energy
E = K = ½ (M-2m) v²
where m is the mass of antimatter and M is the mass of the ship's mass. Factor two is due to the fact that equal amounts of matter and antimatter must be combined
we substitute
m c² = ½ (M-2m) v²
v² = 
let's calculate
v = 
v = 
v = 5.88 10⁷ m / s
Answer:
For this, you need the pythagorean theorem, which is a^{2}+ b^{2}= c^{2}
Your a should be 12, and your b should be 35. So now you can solve for c, which equals 37 miles.
So the answer is 37 miles
Vertical forces:
There is a force of 579N acting upward, and a force of 579N
acting downward.
The vertical forces are balanced ... they add up to zero ...
so there's no vertical acceleration.
Not up, not down.
Horizontal forces:
There is a force of 487N acting to the left, and a force of 632N
acting to the right.
The net horizontal force is
(487-left + 632-right) - (632-right - 487-right) = 145N to the right.
The net force on the car is all to the right.
The car accelerates to the right.
Answer:
17.92 Ω
Explanation:
R₀ = Initial resistance of the aluminum wire at 30.0°C = 7.00 Ω
R = resistance of the aluminum wire at 430.0°C = ?
α = temperature coefficient of resistivity for aluminum = 3.90 x 10⁻³ °C⁻¹
ΔT = Change in temperature = 430 - 30 = 400 °C
Resistance of the wire is given as
R = R₀ (1 + α ΔT)
R = (7) (1 + (3.90 x 10⁻³) (400))
R = 17.92 Ω
