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3 years ago

(04.03 MC)

Physics

2 answers:

Oxana [17]3 years ago

8 0

Option (C ) is the correct answer.

Glucose + oxygen → Carbon Dioxide + Water + Energy

This is the chemical equation for respiration. Respiration is a process in which glucose reacts with oxygen to produce water and carbon dioxide with the liberation of energy.

serious [3.7K]3 years ago

5 0

I belive what your looking for is oxygen

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PSYW - Please Show Your Work

Ad libitum [116K]

Answer:

9.66E4 J

Explanation:

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3 years ago

What mass has a rest energy of 100J?

alexandr1967 [171]

Answer:

option a is correct

Explanation:

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3 years ago

if a gas has a gage pressure of 156 kpa its absolute pressure is approximately .....A... 56 kPa ....B....100 kPa.......C......25

NeX [460]

256 kPa because p-guage + p-absolute + p-atmospheric = 256

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3 years ago

Se lanza verticalmente una esfera con una rapidez de 30m/se. Determinar la rapidez de la esfera a una altura de 40m (g=10m/s2)

sergeinik [125]

$v^2-{v_0}^2=2a(x-x_0)$

dónde $v$ es la velocidad de la esfera, $v_0$ es suya velocidad inicial, $a=-g$ la aceleración debida a la gravedad, $x$ la posición, y $x_0$ la posición inicial. Tomamos $x_0=0\,\mathrm m$ a referirse a la posición de la esfera en el momento que la esfera fue lanzada.

Entonces

$v^2-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-10\,\dfrac{\mathrm m}{\mathrm s^2}\right)(40\,\mathrm m)$

$\implies v^2=100\,\dfrac{\mathrm m^2}{\mathrm s^2}\implies v=\pm10\,\dfrac{\mathrm m}{\mathrm s}$

Esto nos dice que la esfera alcanza una altura de 40 m en dos momentos - una vez hacia arriba y una vez hacia abajo. Sin embargo, independientemente del signo de la velocidad, sabemos que suya magnitud es 10 m/s, y así tenemos una rapidez de 10 m/s también en ambos momentos.

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3 years ago

The time constant for RC circuit with the values of R1 and C1 is 5ms. What will be the time constant for a new RC circuit with t

lions [1.4K]

Answer:

d. 25 ms

Explanation:

In a RC circuit we call time constant to the product of the resistance times the capacitance, which represents the time when the charge reaches to the 63% of the final value, as follows:

$\tau_{1} = R_{1} *C_{1} = 5 ms (1)$

If we have a new circuit with new values for R and C, the time constant will be defined in the same way, as follows:

$\tau_{2} =10* R_{1} *0.5*C_{1} = 5*(R_{1}* C_{1}) = 5* \tau_{1} = 5* 5 ms = 25 ms (2)$

6 0

3 years ago