Which statement is true of cooling down after physical activity? A cool-down is a period of semistrenuous activity after physica
2 answers:
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Answer:
Explanation:
The time period of geosynchronous satellite must be equal to T .
The radius of its orbit will be ( R+ h )
orbital velocity V₀ =
Time period T = 2π( R + h ) / V₀
= 2π( R + h ) x
= R +h
h = - R.
Answer:
Distance of the point where electric filed is 2.45 N/C is 1.06 m
Explanation:
We have given charge per unit length, that is liner charge density
Electric field E = 2.45 N/C
We have to find the distance at which electric field is 2.45 N/C
We know that electric field due to linear charge is equal to
, here
is linear charge density and r is distance of the point where we have to find the electric field
So
r = 1.06 m
So distance of the point where electric filed is 2.45 N/C is 1.06 m